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MatroZZZ [7]
2 years ago
11

The members of a cooking club are making cakes, which they will sell at a street fair for $8 apiece. It cost $30 for a booth at

the fair, and the ingredients for each cake cost $2. At some point, the club members will sell enough cakes so that their sales cover their expenditures. How many cakes will they have sold?
Mathematics
1 answer:
Olin [163]2 years ago
5 0

They need to sell 5 pieces to cover their expenditures (have a profit of zero).

<h3>How many cakes will they have sold?</h3>

We know that the costs are:

  • $30 for the booth at the fair.
  • $2 for each piece of cake they sell.

And the revenue is:

  • $8 for each piece of cake.

So, the profit (the difference between the revenue and the cost) for selling x pieces is:

p(x) = $8*x - $2*x - $30

p(x) = $6*x - $30

We want to find the value of x such that p(x) = 0, then:

0 =  $6*x - $30

x = $30/$6 = 5

They need to sell 5 pieces to cover their expenditures (have a profit of zero).

If you want to learn more about profit:

brainly.com/question/23103804

#SPJ1

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For f(x) = 4x+1 and g(x) =x^2-5 find (f times g) (4)<br><br> apex
Dafna11 [192]

Answer:

(f o g)(4) =  45

Step-by-step explanation:

<u>Step 1:-</u>

Given f(x) = 4 x+1 and g(x) =x^2-5

(f o g )(x) = f(g(x))

Given

(f 0 g)(4)=f(g(4))

f(g(4))=f(4^{2}-5)=f(11)

f(11)=4(11)+1 = 45

Therefore (f o g)(4) =  45

6 0
3 years ago
Help on this problem
GREYUIT [131]
0.77(13.50×40)= 415.8
The answer is $415.8

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3 years ago
The pre-image, ΔSTU, has undergone a type of transformation called a rigid transformation to produce the image, ΔVWX. Compare th
maw [93]

Answer:

all of them

Step-by-step explanation:

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5 0
3 years ago
N is inversely proportional to t and when t is 36 ,N is176 .
sergeinik [125]

Answer:

The answer is below

Step-by-step explanation:

N is inversely proportional to t, therefore:

N ∝ 1/t

Let k be the constant of proportionality, hence we can replace the relationship by:

N = k/t

Given that when t is 36, N is 176. Therefore we can find the value of k:

176 = k / 36

k = 176 * 36 = 6336

N = 6336/t

Also let us find N when t = 6. This is done by substituting t = 6 into the equation and simplifying:

N = 6336/6

N = 1056

8 0
3 years ago
Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
3 years ago
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