The members of a cooking club are making cakes, which they will sell at a street fair for $8 apiece. It cost $30 for a booth at the fair, and the ingredients for each cake cost $2. At some point, the club members will sell enough cakes so that their sales cover their expenditures. How many cakes will they have sold?
1 answer:
They need to sell 5 pieces to cover their expenditures (have a profit of zero).
<h3>
How many cakes will they have sold? </h3>
We know that the costs are:
$30 for the booth at the fair. $2 for each piece of cake they sell.
And the revenue is:
$8 for each piece of cake.
So, the profit (the difference between the revenue and the cost ) for selling x pieces is:
p(x) = $8*x - $2*x - $30
p(x) = $6*x - $30
We want to find the value of x such that p(x) = 0, then:
0 = $6*x - $30
x = $30/$6 = 5
They need to sell 5 pieces to cover their expenditures (have a profit of zero).
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<h2>Given :-</h2>
50 men do 10 hours work daily complete work in 20 days
80 men do job in 50% time
<h2>To Find :-</h2>
<h2>Solution :-</h2>
1 man may do job in (50 × 20) days = 1 man may do job in 1000 days Now,
Now,
When hours reduced 50% then we will multiply days by 2 Total days = 12.5 × 2 = 25 days.
<h2>Hence</h2>
Answer:
you divide -8y by both sides and you would so that means that y=-2.
Step-by-step explanation:
Answer:
37°
Step-by-step explanation:
∠ECF= ∠ACG
∠ACG= 90° - ∠GAC= 90° - 53°= 37°
B IS THE ANSEWER TO THE PROBLEM
