Kayleigh has 3 1/2 gallons of water. She wants to fill up 1/3 cups. How many cups can she fill and how much is left over?

HELP!!! Lucas deposits $250,000 into two investment accounts. Over a year, the first account

prohojiy [21]

The amount deposited in the account that earns 3.6% interest is $57,600 and the amount deposited in the account that earns 2.1% interest is $192,400

The first step is to determine the amount of interest he earned in total over a year

Interest = Amount in the account - amount deposited

$256,114 - $250,000 = $6,114

The second step is to formulate two set of equations and use simultaneous equation to solve the question

a + b = $250,000 equation 1

0.036a + 0.021b = $6,114 equation 2

Where a represent amount deposited in the account that earns 3.6% interest

b represent amount deposited in the account that earns 2,1% interest

Multiply equation 1 by 0.036

0.036a + 0.036b = 9000 equation 3

Subtract equation 2 from 3

2886 = 0.015b

divide both sides of the equation by 0.015

b = $192,400

Substitute for b in equation 1

a + 192,400 = 250,000

a = 250,000 - 192400

a = $57,600

To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults

6 0

3 years ago

What is (1, -2) and (2, 2) as a linear equation

frutty [35]

Answer:

y=4

Step-by-step explanation:

y=2+2/2-1

y=4

8 0

3 years ago

8

blagie [28]

Answer:

The new function is g(x) = x² +1

Step-by-step explanation:

Explanation:-

Given that the function f(x) = x²

From graph ,

The parabola y = x² is shifting to up with '1' units

y = x² +1

The new function is g(x) = x² +1

Verification:-

y = x²+1

Put x=0 ⇒ y =1

The point (0,1) lies on the parabola y = x²+1

similarly put x =1 and y = 2

The Point (1,2) lies on the Parabola y = x²+1

∴ The new graph y = x²+1

3 0

3 years ago

please help this is a math question about geometry !!!! please view the attached images to see the question and the answer choic

jolli1 [7]

Answer:

It is the second picture.

Step-by-step explanation:

4 0

2 years ago

The diagram shows a regular octagon ABCDEFGH. Each side of the octagon has length 10cm. Find the area of the shaded region ACDEH

Zolol [24]

The area of the shaded region /ACDEH/ is 325.64cm²

Step 1 - Collect all the facts

First, let's examine all that we know.

We know that the octagon is regular which means all sides are equal.
since all sides are equal, then all sides are equal 10cm.
if all sides are equal then all angles within it are equal.
since the total angle in an octagon is 1080°, the sum of each angle within the octagon is 135°.

Please note that the shaded region comprises a rectangle /ADEH/ and a scalene triangle /ACD/.

So to get the area of the entire region, we have to solve for the area of the Scalene Triangle /ACD/ and add that to the area of the rectangle /ADEH/

Step 2 - Solving for /ACD/

The formula for the area of a Scalene Triangle is given as:

A = $\sqrt{S(S-a)(S-b)(S-c) square units}$

This formula assumes that we have all the sides. But we don't yet.

However, we know the side /CD/ is 10cm. Recall that side /CD/ is one of the sides of the octagon ABCDEFGH.

This is not enough. To get sides /AC/ and /AD/ of Δ ACD, we have to turn to another triangle - Triangle ABC. Fortunately, ΔABC is an Isosceles triangle.

Step 3 - Solving for side AC.

Since all the angles in the octagon are equal, ∠ABC = 135°.

Recall that the total angle in a triangle is 180°. Since Δ ABC is an Isosceles triangle, sides /AB/ and /BC/ are equal.

Recall that the Base angles of an isosceles triangle is always equal. That is ∠BCA and ∠BAC are equal. To get that we say:

180° - 135° = 45° [This is the sum total of ∠BCA and ∠BAC. Each angle therefore equals

45°/2 = 22.5°

Now that we know all the angles of Δ ABC and two sides /AB/ and /BC/, let's try to solve for /AC/ which is one of the sides of Δ ACD.

According to the Sine rule,

$\frac{Sin 135}{/AC/}$ = $\frac{Sin 22.5}{/AB/}$ = $\frac{Sin 22.5}{/BC/}$

Since we know side /BC/, let's go with the first two parts of the equation.

That gives us $\frac{0.7071}{/AC/} = \frac{0.3827}{10}$

Cross multiplying the above, we get

/AC/ = $\frac{7.0711}{0.3827}$

Side /AC/ = 18.48cm.

Returning to our Scalene Triangle, we now have /AC/ and /CD/.

To get /AD/ we can also use the Sine rule since we can now derive the angles in Δ ABC.

From the Octagon the total angle inside /HAB/ is 135°. We know that ∠HAB comprises ∠CAB which is 22.5°, ∠HAD which is 90°. Therefore, ∠DAC = 135° - (22.5+90)

∠DAC = 22.5°

Using the same deductive principle, we can obtain all the other angles within Δ ACD, with ∠CDA = 45° and ∠112.5°.

Now that we have two sides of ΔACD and all its angles, let's solve for side /AD/ using the Sine rule.

$\frac{Sin 112.5}{/AD/}$ = $\frac{Sin 45}{18.48}$

Cross multiplying we have:

/AD/ = $\frac{17.0733}{0.7071}$

Therefore, /AD/ = 24.15cm.

Step 4 - Solving for Area of ΔACD

Now that we have all the sides of ΔACD, let's solve for its area.

Recall that the area of a Scalene Triangle using Heron's formula is given as

A = $\sqrt{S(S-a)(S-b)(S-c) square units}$

Where S is the semi-perimeter given as

S= (/AC/ + /CD/ + /DA/)/2

We are using this formula because we don't have the height for ΔACD but we have all the sides.

Step 5 - Solving for Semi Perimeter

S = (18.48 + 10 + 24.15)/2

S = 26.32

Therefore, Area = $\sqrt{26.32(26.32-18.48)(26.32-10)(26.32-24.15)}$

A = $\sqrt{26.32 * 7.84*16.32 * 2.17)}$

A = $\sqrt{7,307.72}$ Square cm.

A of ΔACD = 85.49cm²

Recall that the shape consists of the rectangle /ADEH/.

The A of a rectangle is L x B

A of /ADEH/ = 240.15cm²

Step 6 - Solving for total Area of the shaded region of the Octagon

The total area of the Shaded region /ACDEH/, therefore, is 240.15 + 85.49

= 325.64cm²

See the link below for more about Octagons:
brainly.com/question/4515567

8 0

3 years ago