hope can help u !!!!!!!!!!
Answer:
.
See the diagram attached below.
Let the chords be AB and AC with common point A.
AD is the diameter. Join B with D and C with D to form two triangles.
We need to prove that AB=AC.
\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}
In △ABD and△ACD;
Given that ∠BAD=∠CAD−−−−(condition 1)
since AD is diameter,∠ABD=∠ACD=90
0
So ∠ADB=∠ADC−−−−−−−−(condition 2)
AD=AD (common side)−−−−−(condition 3)
So the triangles are congruent by ASA rule.
Hence AB=AC.
Answer:
yes :)
Step-by-step explanation:
The answer is x=5/8. The reason for this is when you divide it equal 0.625 then when you multiply that by 2 it equals 1.25. After you do that you add 5 which is 6.25. Now we divide 4/5 which is 0.8. Now, we multiply 6.25x0.8=5. 5-4=1. Therefore your answer is 5/8. Hope this helps :)
C. 2x + 3
You have many ways to solve this!
You could...
A) multiply all the answer choices by 3x-2 and see what matches
B) Factor the trinomial
C) Divide the trinomial by the binomial using long division
