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3 years ago

What is the value of x in the equation 3(4x-) - 2x+1=3 - (3x-6)?

Mathematics

1 answer:

Margaret [11]3 years ago

4 0

Answer:

x = -4/17

Step-by-step explanation:

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solve the equations below. make sure you say how many solutions each equation has(MCC.8.EE.7a) A. 5p-9=7p-19 b. 5p-9= 5p-19 C. 5

Sedaia [141]

<h3>Answer:</h3>

A) p = 5, one solution
B) no solutions
C) infinite solutions

<h3>Step-by-step explanation:</h3>

A) Add 19-5p to each side of the equation:

... 10 = 2p

... 5 = p . . . . . divide by the coefficient of p

B) Subtract 5p from both sides of the equation:

... -9 = -19 . . . . . there is <em>no value of p</em> that will make this true. (No solution.)

C) Subtract 5p from both sides of the equation:

... -9 = -9 . . . . . this is true for <em>every value of p</em>. (Infinite solutions.)

6 0

3 years ago

Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil

Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

$P(X\leq x)=1-e^{\frac{-x}{\lambda}}$ , where $\lambda$ is the mean of the distribution.

As per given , we have

Average tread-life of a certain brand of tire : $\lambda=\text{42,000 miles }$

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

$P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872$

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

8 0

3 years ago

What is the equation of the line with m = 3 and b = 8.25?

quester [9]

Y=3x + 8.25
...................

6 0

3 years ago

Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are

Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0

3 years ago

9, 21, 7, 11, 13, 21, 5, 14, whats the range?

maria [59]

16 would be the range. The lowest value is 5, and the highest value is 21. You just subtract those two which gives you 16! (:

4 0

3 years ago

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What is the value of x in the equation 3(4x-) - 2x+1=3 - (3x-6)?​

What is the value of x in the equation 3(4x-) - 2x+1=3 - (3x-6)?