Answer:
The answer is "Option a".
Explanation:
The B.I. is a method, methodology, software, and development set that makes raw data usable and relevant, which facilitates improved decision-making and competitive opportunities, and certain choices were wrong, which can be described as follows:
- In option b, The A.I is uses in the machines, that's why it is not correct.
- In option c, It is used to analyze the data, which used in business. that's why it is not correct.
- In option d, It is wrong, because it a part of A.I.
Answer:
showProduct(int,double)
for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.
Explanation:
The code is
- <em>public static void showProduct (int num1, double num2){</em>
- <em> int product;</em>
- <em> product = num1*(int)num2;</em>
- <em> System.out.println("The product is "+product);</em>
- <em> }</em>
showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.
If showProduct( 10,10.0) is called the output will be 'The product is 100'.
Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is <em>product=num1*(int)num2</em>, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.
This is necessary in JAVA and many other programming languages as you <u>cannot</u><u> multiply two different datatypes</u> (here one is int and another is double). Either both of them should be of type int or both should be of type double.
Answer:
it executes the commands sent to it by the applica software .
names = ["Kevin", "Joe", "Thor", "Adam", "Zoe"]
names.sort()
for x in names:
if x == "Thor":
break
else:
print(x)
I made up my own names for the sake of testing my code. I wrote my code in python 3.8. I hope this helps.
