Multiply what he makes a month by six
Answer:
b. shift from curve CD to curve EF.
Required Details of the Question:
The image of the curve required to answer the question has been attached.
Explanation:
A production possibilities curve shows various combinations of the amounts of two goods( in this case capital and consumer goods) which can be produced within the given resources and a graphical representation showing all the possible options of output for the two products that can be produced using all factors of production.
Now the growth of an economy is best illustrated in the image by the shift from curve CD to curve EF, this means that as the nation's production capacity increases, its production possibilities curve shift outward showing an increase in production of both goods.
Answer:
a. The cell tower forwards the call to the wireless provider's Mobile Telephone Switching Office
Explanation:
When a cell phone user begins to make a call, it is picked up by the cell tower located in the cell in which the cell phone is located and that belongs to the user's wireless provider. The next step in this process is that the cell tower forwards the call to the wireless provider's Mobile Telephone Switching Office.
Answer:

Explanation:
When we convert any decimal number into the hexadecimal number we have to divide that number with 16.
Now according to question the decimal number is 35.
Now to convert this in hexadecimal divide it with 16.

This means the quotient is 2 and the remainder is 3.
Therefore the value of hexadecimal is,

Therefore,
.
Answer:
int[ ][ ] X = new int[5][5];
It can also be declared and initialized this way:
int[][] X = {
{1,2,3,6,8},
{4, 5, 6, 9},
{7,5,6,8,9},
{8,5,8,8,9},
{10,2,6,8,11},
};
Explanation:
Above is a declaration of a two-dimensional array that can hold 5*5=25 int values. A java program is given below:
public class JavaTwoD{
public static void main(String args[ ]) {
// creating the 5X5 array
int[ ][ ] X = new int[5][5];
// looping through the array to add elements
for (int i = 0; i < X.length; i++) {
for (int j = 0; j < X[i].length; j++) {
X[i][j] = i * j;
}
}