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1 year ago

Please help me it is an easy question

Mathematics

1 answer:

Ugo [173]1 year ago

5 0

Answer:

200 yd²

Step-by-step explanation:

A = 17 yd

B = 15 yd

C = 2 yd

D = 8 yd

b) Area of rectangle = length * width

$\sf Area \ of \ 2 \ triangle = 2* \dfrac{1}{2}* base * height = base* height\\\\$

Area of right triangular prism = Areas of two triangle + area of the upper rectangle + area of middle rectangle + area of below rectangle

= 8 * 15 + 17 * 2 + 15 *2 + 8*2

= 120 + 34 + 30 + 16

= 200 yd²

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2 years ago

Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

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$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
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\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
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\\
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3 years ago

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Answer:

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Step-by-step explanation:

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