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Natasha_Volkova [10]
3 years ago
8

Is 4.95 a terminating decimal

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
6 0

Answer:

Definitely

since the definition of a terminating decimal is one that has an ending, and a Repeating decimal is one that never ends.

Step-by-step explanation:

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Please help me this is due today WORTH 40pts
Softa [21]

Answer:

This number "four" is the maximum possible number of positive zeroes (that is, all the positive x-intercepts) for the polynomial f (x) = x 5 – x 4 + 3x 3 + 9x 2 – x + 5. Affiliate However, some of the roots may be generated by the Quadratic Formula , and these pairs of roots may be complex and thus not graphable as x -intercepts.

can calculate and graph the roots (x-intercepts), signs, Local Maxima and Minima, Increasing and Decreasing Intervals, Points of Inflection and Concave Up/Down intervals.

Step-by-step explanation:

5 0
3 years ago
F(x)=-3x^2-6x<br><br> Find f(−9)
Anni [7]

Answer:

Your brain.

Step-by-step explanation:

All you have to do is plug the value of -9 into the equation everywhere you see an 'x' and if you are being asked this question I assume you have basic mathematical skills

3 0
3 years ago
Read 2 more answers
Write 3/5 as a % 60%
Alinara [238K]

Answer:

(3/5)× 100

0.6 ×100= 60%

yw

3 0
1 year ago
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Find the percent of discount for $70 discounted to $63. Round to the nearest percent.
aksik [14]
70 x P = 63
P=63/70 = 0.9
Since P is 1-the discount
1-discount= 0.9
discount is 0.1, or 10 %
5 0
3 years ago
Write the quadratic equation whose roots are 5 and 1, and whose leading coefficient is 5
zepelin [54]

Answer: the equation is

5x^2 -30x - 25

Step-by-step explanation:

A quadratic equation is one in which the highest power of the unknown is 2.

The general form of a quadratic equation is expressed as

ax^2 + bx + c

Where c is a constant and a is the leading coefficient

Assuming we want to write the quadratic equation in x, from the information given, the given roots are 5 and 1 and the leading coefficient is 5. We will just multiply the expression by the leading coefficient.

Therefore, the linear factors of the quadratic will be (x-5) and (x-1)

With the leading coefficient as 5, the equation becomes

5(x-5)(x-1)

= 5(x^2 - x - 5x + 5)

= 5(x^2 - 6x + 5)

= 5x^2 -30x - 25

3 0
2 years ago
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