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1 year ago

A point in quadrant iii is reflected across the y-axis. what is true about the new location? check all that apply.

1 answer:

6 0

The new location is in Quadrant IV and The new location has a positive x-coordinate and a negative y-coordinate. Hence, option b and c are correct.

<h3>What are Coordinates?</h3>

The horizontal and vertical addresses of any pixel or addressable point on a computer display screen are, respectively, represented by the x and y coordinates.
The pixel (pixel 0) on the far left of the screen serves as the beginning point for the x coordinate, which is a predetermined distance along the horizontal axis of a display.
The y coordinate is a specified range of pixels along a display's vertical axis, starting at the top pixel (pixel 0). The x and y coordinates work together to pinpoint any particular pixel location on the screen.
As values relative to any beginning point on the screen or any portion of the screen, such as an image, x and y coordinates can also be given.

Solution:

If the point were to reflect across the y-axis, it would fall into the fourth quadrant.

Additionally, the coordinates will be positive for the x-axis and negative for the y-axis.

Learn more about similar numerical on coordinate:

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I hope you are trying to ask the question below:

Question

A point in Quadrant III is reflected across the y-axis. What is true about the new location? Check all that apply.

a. The new location is in Quadrant II.

b. The new location is in Quadrant IV.

c. The new location has a positive x-coordinate and a negative y-coordinate.

d. The new location has a negative x-coordinate and a positive y-coordinate.

e. The new location has negative x- and y-coordinates.

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In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and

exis [7]

Answer:

Step-by-step explanation:

cartesian plane :

quadrant 1 : both x and y are positive

quadrant 2 : x is negative, y is positive

quadrant 3 : both x and y are negative

quadrant 4 : x is positive and y is negative

(-2,4)......we have x is negative and y is positive...so we are in quadrant 2

(3,-1)....we have x is positive and y is negative...in quadrant 4

(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x

(1,2)....both are positive....located in quadrant 1

(-3,-5)...both are negative.....quadrant 3

5 0

3 years ago

39/250 in simplest form

OleMash [197]

Getting the simplest form of a fraction is the same with getting its lowest term. Reducing fractions to its lowest term is a very simple thing to do. Here's how to simplify fractions:

There are two ways in simplifying fractions. The first method is to equally divide both numerator and denominator which results to only whole numbers. Getting the GCF (Greatest Common Factor) or GCD (Greatest Common Divisor) is the second method.

As to the fraction above, 39/250, the second method is applicable.
Let us get the GCF of 39 and 250
39= 1,3,13,39
250= 1, 2, 5, 10, 25, 50, 125, 250

Therefore, the GCF of 39 and 250 is 1. We can conclude then that 39/250 is already on its simplest form thus;
39 ÷ 1 is equal to 39
250 1 250

7 0

2 years ago

The average price of a barrel of crude oil in a recent year was 65.37. which estimated price is incorrect.

Nutka1998 [239]

Answer:

65.37 isn't an estimated price, it's an exact price....

5 0

2 years ago

Read 2 more answers

The time spent dancing (minutes) and the amount of calories burned can be modeled by the equation c = 5.5t. Which table of value

pishuonlain [190]

To build the table you just have to give values to t and then calculate the corresponding c a per the model.

If the model is c = 5.5 t this is the table

t    c
   5.5 t

0 5.5(0) = 0

1 5.5(1) = 5.5

2      5.5(2) = 11.0

3 5.5(3) = 16.5

4 5.5(4) = 22.0

5 5.5(5) = 27.5

The viables solutions are all where t is equal or greater than 0. You can even use decimal values for t. You cannot use negative values for t.

5 0

3 years ago

Read 2 more answers

Point A is at (-1,-9) and Point M is at (0.5,-2.5).

leva [86]

Midpoint Formula: $(\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$

So firstly, let's start with the x-coordinates. Since we know the midpoint's x-coordinate and point A's x-coordinate, we can solve for point B's x-coordinate as such:

$\frac{-1+x}{2}=0.5\\\\-1+x=1\\\\x=2$

Next, do the same thing except solve for the y-coordinate and using point A's y-coordinate and the midpoint's y-coordinate:

$\frac{-9+y}{2}=-2.5\\\\-9+y=-5\\\\y=4$

Putting it together, point B's coordinates are (2,4).

4 0

2 years ago