Answer:
The area of the new reduced parallelogram after dilation is 8 cm^2
Step-by-step explanation:
Mathematically, the area of a parallelogram = b * h
before dilation, area of the parallelogram = 8 * 4 = 32 cm^2
After dilation by a factor of 1/2, the base of the parallelogram becomes 1/2 * 8 = 4cm while the height becomes 1/2 * 4 = 2cm
Thus, the area of the dilated parallelogram is 4 * 2 = 8 cm^2
The number of races the team need to win today for the team to have a 75% success rate is 15
Number of attempt = 45
Number of winnings = 30
Percentage won so far = 30/45 × 100
= 66.67%
let
x = Number of races that tfe team needs to win to have 75% success rate
(30 + x) / (45 + x) = 0.75
Cross product
30 + x = 0.75(45 + x)
30 + x = 33.75 + 0.75x
x - 0.75x = 33.75 - 30
0.25x = 3.75
x = 3.75 / 0.25
x = 15
Therefore, the number of races the team need to win today for the team to have a 75% success rate is 15
Learn more about percentage:
brainly.com/question/7225231
ANSWER= 14 oz bottle
6.98 - 2 = 4.98 (14oz)
19.99 - 2 = 17.99 (28oz)
28 is triple the price when it’s only two times bigger
You’re right it’s G because when you are going to your righ it’s goin by 7 n same on the left side
Answer:
P(A | F) = 81.81%
There is 81.81% probability that worker was taught by method A given that he failed to learn it correctly.
Step-by-step explanation:
The failure rate is 15% for A which means that
P(F | A) = 0.15
The failure rate is 5% for B which means that
P(F | B) = 0.05
Method B is more expensive and hence is used only 40% of the time which means that
P(B) = 0.40
Which means that A is used the other 60% of the time
P(A) = 0.60
A worker is taught the skill by one of the methods but fails to learn it correctly.
We are asked to find the the probability that he was taught by method A.
So that means we want to find out
P(A | F) = ?
We know that according to Baye's rule,

Substitute the given probabilities into the above equation

Therefore, there is 81.81% probability that worker was taught by method A given that he failed to learn it correctly.