First lets distribute the 5x
5x^2 + 30x = -50
Lets divide every term by 5
x^2 + 6x = -10
To complete the square we have to half the b value, which in this case is 6. Then square it.
Half of 6 is 3, 3 squared is 9
Add that to both sides of the equation
x^2 + 6x + 9 = -1
Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment)
(x+3)^2 = -1
Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and
x = -3 + i
Answer:
Step-by-step explanation:
The rules For fractions: Multiple Denominator to Denominator and Numerator to numerator!
Ok: For number 1
3/5*1/1= 3/5
Number 2
3/4*9/4=27/16= 1 11/16
Number 3
14/21=2/3*33/7=66/21= 3 3/21= 3 1/7
Number 4
6/18*9/42= 1/3*3/14= 3/42= 1/14
Number 5
22/15*45/4= 33/2=16 1/2
Number 6
3/28* 35/6= 105/168= 5/8
Number 7
2/7*35/12=60/84=5/6
Number 8
16/15*21/24=16/15* 7/8=112/120=14/15
Hope It helps!!!!
Triangles are the easiest shape to make a hexagon out of. You can do this by lining up 6 triangles where each base of the triangle lines up.
Answer: There will enough to paint the outside of a typical spherical water tower.
Step-by-step explanation:
1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:
![V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7Dr%5E%7B3%7D%5Cpi%5C%5C%5Cfrac%7B3V%7D%7B4%5Cpi%7D%3Dr%5E%7B3%7D%5C%5Cr%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
2. Substitute values:
![r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3%2866%2C840.28ft%5E%7B3%7D%29%7D%7B4%5Cpi%7D%7D%3D25.17ft)
3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:
3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.
As you can see, there will enough to paint the outside of a typical spherical water tower.
No not always the answer has to be irrational.
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