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hjlf
4 years ago
15

Can anyone help me with this problem?

Mathematics
1 answer:
Tom [10]4 years ago
6 0
Williams= 26
Porter= 28
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How do i express x^2-3x into the form of (x-m)^2+n. I will give brainliest to correct answer
mel-nik [20]

Step-by-step explanation:

let's simply do the multiplications and then compare with the original.

(x-m)² + n

right ?

or is it

{(x - m)}^{2 + n}

let's go for the first.

x² - 2mx + m² + n = x² - 3x

-2mx + m² + n = -3x

fun there we see two things :

-2m = -3

m = 3/2

and

m² + n = 0

(3/2)² = -n

9/4 = -n

n = -9/4

so our transformed expression looks like

(x - 3/2)² - 9/4

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3 years ago
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Fantom [35]

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2 years ago
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The<br> Calculate the perimeter of<br> Following Shape:<br> 8cm<br> 5cm
mina [271]

Answer:

where is your shape

Step-by-step explanation:

firstly give shape then we find out perimeter

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7 0
3 years ago
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Why is - t - 3 written as 3 - t? Is it wrong if it is left as -t -3?
Eddi Din [679]

-t-3 and 3-t are not the same since t-3 would result in a negative answer since both -t and -3 are negative. While in t-3 t is positive and -3 is negative. it is wrong if its left as t-3 since -t-3=3-t is false.

4 0
3 years ago
In investing $6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple inter
ddd [48]

Answer:

$ 2,600 was invested at 4% and $ 3,600 was invested at 9%.

Step-by-step explanation:

Given that in investing $ 6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest, and the rest was invested in a riskier mini-mall development plan paying 9% annual simple interest, and the combined interest earned for the first year was $ 428, to determine how much money was invested at each rate, the following calculation must be performed:

3000 x 0.04 + 3200 x 0.09 = 408

2500 x 0.04 + 3700 x 0.09 = 433

2600 x 0.04 + 3600 x 0.09 = 428

Therefore, $ 2,600 was invested at 4% and $ 3,600 was invested at 9%.

7 0
3 years ago
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