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1 year ago

Grade 9 math useing frist diff is this a linear relation yes or no show your work

Mathematics

1 answer:

Dahasolnce [82]1 year ago

5 0

Answer:

not linear since all first differences are not equal

Step-by-step explanation:

To find the first differences, subtract each y value from the next y value.

Use only y values.

here are the 4 first differences you need to calculate.

1 - 0 = 1

4 - 1 = 3

9 - 4 = 5

16 - 9 = 7

Now you place them in the appropriate column in the table.

x y first difference

0 0 1

1 1 3

2 4 5

3 9 7

4 16

If the first differences were all equal, the function would be a linear function.

In this case, the first differences are all different, 1, 3, 5, 7, so the function is not linear.

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Identify the function as a growth or decay function. y = (1/2)x

tangare [24]

Answer:

This would be a decay function.

Step-by-step explanation:

When a function is a growth function that means that it is growing but a decay function means that it is getting smaller.

8 0

2 years ago

Write an expression equivalent to `m+m+m+m` that is a product of a coefficient and a variable. Please include an explanation!

Marina CMI [18]

Answer:

Step-by-step explanation:

it would be 4m because there are four different copies and the variable being used originally is 'm'. therefore, we can move it around and since addition is basically the longer version of multiplication, we would correct this to 4m.

good luck :)

i hope this helps

have a nice day !!

6 0

2 years ago

Read 2 more answers

Identify all solutions for a triangle with A = 38 degrees b = 10, and a= 8. Round to the nearest tenth.

rjkz [21]

Answer:

A = 38°

B = 50.32°

C = 91.68°

a = 8

b = 10

c = 12.77

Step-by-step explanation:

The first thing is to find the angle B, like this:

sin B = b * sin A / a = 10 * sin (38 °) / 8

sin B = 0.77

B = arc sin (0.77)

B = 50.32 °

For angle C, it would be:

C = 180 - 38 - 50.32

C = 91.68 °

Side c, we calculate it like this:

c = a * sin C / sin A = 8 * sin (91.68 °) / sin (38 °)

c = 12.77

5 0

3 years ago

To solve a system of inequalities, you just need to graph each inequality and see wich points are in the overlap of the graphs.

GrogVix [38]

<h3>Answer: True</h3>

This is often how many math teachers and textbooks approach problems like this. The overlapped region is the region in which satisfies every inequality in the system. Be sure to note the boundary of each region whether you're dealing with a dashed line or a solid line. Dashed lines mean points on the boundary do not count as solution points, whereas solid boundaries allow those points as part of the solution set.

Side note: This is assuming you're dealing with 2 variable inequalities. If you only have one variable, you don't need to graph and instead could use algebra. Graphing doesn't hurt though.

3 0

2 years ago

Desmond really like Legos. Last Saturday Desmond counted his Legos and realized that

Burka [1]

Answer: 14 red, 7 green, 44 blue

Step-by-step explanation:

First, use the letter r as a variable to represent the number of red Legos. The number of green Legos (g) is 7 less than the number of red Legos, or g = r-7. The number of blue Legos (b) is 2 more than 3 times the number of red Legos, or b = 3r+2. The total number of Legos is the number of red + green + blue Legos, which can be represented as 65 = r+g+b.

Substitute the equations for g and b in. This should give you a final equation of 65 = r+(r-7)+(3r+2). To solve for the number of red Legos, first add up all of the terms to get 65 = 5r-5. Now add 5 to each side (70 = 5r). Finally, divide each side by 5 (r = 14).

To find the number of green Legos, substitute the number of red Legos (14) into the equation for the green Legos (g = r-7). This should get you the equation g = 14-7 which simplifies to g = 7.

To find the number of blue Legos, substitute the number of red Legos (14) into the equation for the blue Legos (b = 3r+2). This gives you the equation b = (3*14)+2. First, multiply 3 and 14 to get b = 42+2. Finally, add them together to get b = 44.

6 0

2 years ago