<h3>Problem Solution</h3>
Assuming the spool is a cylinder and the circumference we're winding around is that of a circle with the given area, we can write the relation between circumference and area as
... C = 2√(πA)
10 times the circumference is then
... 10C = 20√(π·20 cm²) = 40√(5π) cm ≈ 159 cm
<h3>Formula Derivation</h3>
The usual formulas for circumference and area are
... C = 2πr
... A = πr²
If we multiply the area formula by π and take the square root, we get
... πA = (πr)²
... √(πA) = πr
Multiplying this by 2 gives circumference.
... C = 2√(πA) = 2πr
Tonya is 14 (17 - 3)
<span>Kevin is 7 </span>
<span>Uncle Rob is 51 (3 x 17 = 54, less 3)</span>
First we have to work out everything inside the parentheses (according to PEMDAS):
9 × 2 = 18
4 - 2 = 2
Now, we can rewrite the expression:
4 + 18 ÷ 2 + 1
According to PEMDAS, we should complete the division in the middle first:
18 ÷ 2 = 9
Now we can rewrite the expression again:
4 + 9 + 1
And now it's as simple as just adding the three numbers together:
4 + 9 + 1 = 14
Your final answer is 14. :)
The answer is Tuesday there will be 15 teachers for 179 students and 12 times 15 is 180
Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.
Step-by-step explanation:
Since we have given that
ΔPQS, and ΔSQR,
Consider, ΔPQS,
As we know that " the length opposite to the largest angle is the shortest segment."
So, According to the above statement.
Similarly,
Consider, ΔSQR,
Again applying the above statement, we get that,
Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.
