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Archy [21]
3 years ago
6

List all the perfect squares to15

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100

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!!WILL MARK BRAINLIEST!!!<br><br> please provide a small explanation with it too
Ipatiy [6.2K]

Answer:

(-2, 7); (See attachment)

Step-by-step explanation:

x + 2y = 12

7x + 2y = 0

x + 2y = 12

x = -2y + 12

Solve for y:

7x + 2y = 0

7 (-2y + 12) + 2y = 0

-12y + 84 = 0

-12y = -84

y = 7

Solve for x:

x = -2y + 12

x = -2 (7) + 12

x = -2

x = -2, y = 7

4 0
3 years ago
danielle has $35 to spend on birthday presents for 2 of her friends. she has already spent a total of $6 on the cards. if she wa
Klio2033 [76]
Well this is simple all you have to do is subtract 6 dollars from 35 lets do that first
35 - 6 = 29 
so she has 29 dollars to spend on each friend and she only has two....
so lets divide 29 and 2
29/2 = 14.5 
so she can spend $14.50 on each of her friends:)

merry christmas
8 0
3 years ago
A woman is ordering pizza for a party she can get 3 large pizzas for $26 at this rate what will 12 large pizzas cost?
BARSIC [14]

Answer:104

Step-by-step explanation: if three pizzas cost $26 and you buy 12 pizzas so 4 X 26 = 104

8 0
3 years ago
1) Jodi liked to collect stamps. On 3 different days she bought 6 stomps. Then she
mr Goodwill [35]

Answer:

4

Step-by-step explanation:

6-4+2*5=12

12/3

4

6 0
3 years ago
Marie made a model (shown below) of the square pyramid she plans to build when she grows up. Find the surface area of the model.
TEA [102]

Answer:

144m²

Step-by-step explanation:

The the model made by Marie is attached in the diagram below.

The square pyramid model that Marie has in mind of building has 4 congruent triangular faces on the four sides of the square pyramid, and 1  base square. Therefore the surface area of the square pyramid = area of the square + area of 4 triangles = b² + 4(1/2*b*h)

Given that b = 8, and h = 5, we have:

Surface area = 8² + 4(1/2*8*5)

= 64 + 4(20)

= 64 + 80

SA of the square pyramid = 144m²

3 0
3 years ago
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