Answer:
(3,0)
Step-by-step explanation:
2x + 2y = 6 divide thru by 2 and you get x + y = 3
Name x + y = 3 equation (1) and x - y = 3 equation (2)
Add equations (1) and (2)
(1) x+ y = 3
(2) <u> x - y = 3 </u>
2x = 6
x = 3
Substitute x = 3 into equation (1). So, 3 + y = 3
y = 0
Answer:
T = 200 months
Step-by-step explanation:
Given the model to be
dp/dt = p(10-1-10-7p) where p(0) = 6000
dp/dt = p(-1-7p)
dp/dt = -p+7p²
But since P(0) = 6000
We plug this value into the equation
P = -6000+7(6000)²
P = -6000+252000000
P = 251994000. .limiting value
Differentiating dp/dt w.r.t p
dp/dt = -1+14p
dp'/dt = 14p-1
Plugging p(0) = 6000 into the above we have that
dp'/dt = 14(6000)-1
P' = 84000
Time population would be equal to 3/2 the limiting value
T = 3/2× 84000 = 126000
T = 25199400/126000
T = 199.99months
T = 200 months.
Answer:
h=15.25
Step-by-step explanation:
10h + 42.75 = 195.25
Isolate the variable by dividing each side by factors that don't contain the variable.
h=15.25