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WINSTONCH [101]
2 years ago
6

Determine if

Mathematics
1 answer:
Gnesinka [82]2 years ago
7 0

The values of a and b are 1/4 and 1/5 respectively

<h3>How to determine the true statement?</h3>

The function is given as:

16x^2 - 25y^2 = 1

The above function is a horizontal hyperbola.

A horizontal hyperbola that passes through the origin is represented as:

\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1

Rewrite 16x^2 - 25y^2 = 1 as

\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1

By comparison, we have:

a^2 = \frac{1}{16}

b^2 = \frac{1}{25}

Solve for  a and b

a = \frac{1}{4}

b = \frac{1}{5}

Hence, the values of a and b are 1/4 and 1/5 respectively

Read more about hyperbola at:

brainly.com/question/27799190

#SPJ1

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What is the solution to this set of equations?
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Answer:

(3,0)

Step-by-step explanation:

2x + 2y = 6  divide thru by 2 and you get  x + y = 3  

Name   x + y = 3  equation (1) and  x - y = 3 equation (2)

Add equations (1) and (2)  

 (1)   x+ y = 3

 (2) <u> x - y = 3   </u>  

        2x = 6

          x = 3  

Substitute x = 3 into equation (1).  So, 3 + y = 3

                                                                    y = 0

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3 years ago
(7x8-(-10))divided by 6+(-6)
maw [93]

the answer is 66 i think

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3 years ago
A model for the population p(t) in a suburb of a large city is given by the initial-value problem dp dt = p(10−1 − 10−7p), p(0)
irina1246 [14]

Answer:

T = 200 months

Step-by-step explanation:

Given the model to be

dp/dt = p(10-1-10-7p) where p(0) = 6000

dp/dt = p(-1-7p)

dp/dt = -p+7p²

But since P(0) = 6000

We plug this value into the equation

P = -6000+7(6000)²

P = -6000+252000000

P = 251994000. .limiting value

Differentiating dp/dt w.r.t p

dp/dt = -1+14p

dp'/dt = 14p-1

Plugging p(0) = 6000 into the above we have that

dp'/dt = 14(6000)-1

P' = 84000

Time population would be equal to 3/2 the limiting value

T = 3/2× 84000 = 126000

T = 25199400/126000

T = 199.99months

T = 200 months.

5 0
3 years ago
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if y is the midpoint of xz, y is located at (3,-1), and z is located at (11,-5), find the coordinates of x
svlad2 [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ X(\stackrel{x_1}{x}~,~\stackrel{y_1}{y})\qquad Z(\stackrel{x_2}{11}~,~\stackrel{y_2}{-5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{11+x}{2}~~,~~\cfrac{-5+y}{2} \right)=\stackrel{\stackrel{midpoint}{y}}{(3,-1)}\implies \begin{cases} \cfrac{11+x}{2}=3\\[1em] 11+x=6\\ \boxed{x=-5}\\ \cline{1-1} \cfrac{-5+y}{2}=-1\\[1em] -5+y=-2\\ \boxed{y=3} \end{cases}

7 0
4 years ago
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Geraldine makes $10 per hour at her part-time job. During one week, she also earned $42.75 in tip money, and her final pay for t
erik [133]

Answer:

h=15.25

Step-by-step explanation:

10h + 42.75 = 195.25

Isolate the variable by dividing each side by factors that don't contain the variable.

h=15.25

4 0
3 years ago
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