Answer:
Step-by-step explanation:
The problem is:
<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>
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This problem is about algebraic language. We just need to express the ordinaty language into an equation.
We know the words less means difference. So, let's call Argos' weight and Roco's weight. We can expresse the given problem as
Notice that we applied a difference due to the word "less" in the problem.
Therefore, Argo's weight is given by the expression
Let be Z the money ;
We have ( 40 / 100 ) x Z = $85 ;
( 4 / 10 ) x Z = $85 ;
( 2 / 5 ) x Z = $85 ;
Z = $( 85 x 5 ) ÷ 3 ;
Z = $425 ÷ 3 ;
Z = $141,66 ≈ $142 ;
5/ 1+1= 5/2
1+4/1^2-3(1)-4= 5/-6
5/2 - 5/-6 does not equal zero
It rained on 15% of those days
Answer:
solution is (- 3, 5 )
Step-by-step explanation:
given the 2 equations
6x - y = - 23 → (1)
8x + 3y = - 9 → (2)
rearrange (1) expressing y in terms of x
y = 6x + 23 → (3)
Substitute y = 6x + 23 into (2)
8x + 3(6x + 23 ) = - 9
8x + 18x + 69 = - 9
26x + 69 = - 9 ( subtract 69 from both sides )
26x = - 78 ( divide both sides by 26 )
x = - 3
substitute x = - 3 into (3)
y = (6 × - 3 ) + 23 = - 18 + 23 = 5
solution is (- 3, 5 )