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tiny-mole [99]
2 years ago
6

Which of these is equal to ⅔ × ¾ × ⅗?

Mathematics
2 answers:
Sphinxa [80]2 years ago
7 0

Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers)  and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5  would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor.  I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers.  I will choose 3.  I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

Paladinen [302]2 years ago
3 0

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathsf{\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{3}{5}}

\huge\textbf{Simplifying:}

\mathsf{\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{3}{5}}

\mathsf{= \dfrac{2\times3\times3}{3\times4\times5}}

\mathsf{= \dfrac{6\times3}{12\times5}}

\mathsf{= \dfrac{18}{60}}

\mathsf{= \dfrac{18\div3}{60\div 3}}

\mathsf{= \dfrac{6}{20}}

\mathsf{= \dfrac{6\div2}{20\div2}}

\mathsf{= \dfrac{3}{10}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\frak{\dfrac{3}{10}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>~\frak{Amphitrite1040:)}</h3>
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10 watermelons have an average weight of 4.3 pounds and 5 pumpkins have an average weight of 3.4 pounds. What is the average wei
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Since the average is the sum divided by the count, the sum is the average times the count.

So the sum of the weights of the watermelons is 10(4.3)=43 pounds.

The sum of the weights of the pumpkins are 5(3.4)=17 pounds

The sum of the weight of the fruits is 43+17=60 pounds

Dividing by 15 fruits gives an average item weight of 60/15 = 4 pounds

6 0
3 years ago
Read 2 more answers
Which situation describes a car that can travel $40 miles per gallon of gasoline?
Salsk061 [2.6K]

Answer:

A car can travel 80 miles on 2 gallons of gasoline.

Step-by-step explanation:

8 0
3 years ago
It is thought that not as many Americans buy presents to celebrate Valentine's Day anymore. A random sample of 40 Americans yiel
evablogger [386]

Answer:

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

 (0.3672 , 0.7328)

Step-by-step explanation:

<u><em>Explanation:</em></u>-

Given Random sample size n =40

Sample proportion

                            p = \frac{x}{n} = \frac{22}{40} = 0.55

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

   

          (p-Z_{\alpha } \sqrt{\frac{pq}{n} } , p + Z_{\alpha } \sqrt{\frac{pq}{n} } )

         

The Z-value Z₀.₉₈ = Z₀.₀₂ = 2.326

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

    (0.55-2.326\sqrt{\frac{0.55 X0.45}{40} } , 0.55 + 2.326\sqrt{\frac{0.55 X0.45}{40} } )

  ( 0.55 - 0.1828 , 0.55 + 0.1828)

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6 0
3 years ago
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Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea
Nataly [62]

Answer:

Option C.

Step-by-step explanation:

The given expression is  

\sqrt{128x^8y^3z^9}

It can be written as

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=\sqrt{8^2\cdot 2\cdot (x^4)^2\cdot y^{2}\cdot y\cdot (z^{4})^2\cdot z}

=\sqrt{(8x^4yz^4)^2\cdot 2yz}

=8x^4yz^4\sqrt{2yz}

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6 0
3 years ago
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Answer:

D.

D.

A.

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