All categories

3 years ago

Tell whether the set of ordered pairs {(3, −6), (4, −9), (5, −12), (6, −15)} satisfies a linear function. Explain.

Mathematics

1 answer:

Mademuasel [1]3 years ago

4 0

Answer:

Yes, the x value is increasing by one every time, and the y value is decreasing by 3 every time.

Step-by-step explanation:

You might be interested in

Please help with these

kherson [118]

The answers are as follows.

a. 9x

In order to get this, you need to reevaluate 64 as a base of 4. Since 64 is equal to 4^3, we can rewrite the right side as

64^3x = (4^3)^3x = 4^9x

Which gives you the first answer.

b. 10

Similar to the first problem, we need to express 16 as a base of 2. 2^4 is equal to 16, so we use that in it's place and simplify.

16^5/2 = (2^4)^5/2 = 2^20/2 = 2^10

c. Sqrt(7.31)

This one is more simple. Raising something to a 1/2 power (.5) is the same as taking the square root.

4 0

3 years ago

How many feet are shorter than 20 centimeters

Veseljchak [2.6K]

1 foot is shorter that 20 centimeters

8 0

4 years ago

Quick please no links or anything just the straight up answer answer both please

bearhunter [10]

Answer: B. 41

skfjfhdjkslskfjf

6 0

3 years ago

Read 2 more answers

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

8 0

3 years ago

What is the remainder of (x 3 - 6x 2 -9x + 3) ÷ (x - 3)?

pogonyaev

x3 - 6x2 - 8x - 3
—————————————————
x - 1

3 0

3 years ago

Read 2 more answers