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inna [77]
2 years ago
12

In the parallelogram below, y = [? ]° 2 Z 1240 33%

Mathematics
2 answers:
Talja [164]2 years ago
4 0

Answer:

y = 33°

Step-by-step explanation:

The diagonal of the parallelogram (a transversal) intersects two opposite and parallel sides of the parallelogram  

Then

The angles of measures y° and 33° are Alternate interior angles

Then

they are congruent.

In other words , y = 33°

Ber [7]2 years ago
3 0

Answer:

y = 33

Step-by-step explanation:

Angle y and 33 are alternate interior angles since the figure is a parallelogram and alternate interior angles are equal

y = 33

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The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
xxTIMURxx [149]

Step-by-step explanation:

Let the initial population of a community be P0 and the population after time t is P(t).

If the population of a community is known to increase at a rate proportional to the number of people present at time t, this is expressed as:

P(t) = P_0e^{kt}

at t = 5 years, P(t) = 2P0

substitute:

2P_0 = P_0e^{5k}\\2 = e^{5k}\\ln2 = lne^{5k}\\ln2 = 5k\\k = \frac{ln2}{5}\\k = 0.1386

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at t = 3, P(t) = 9000

a) Substitute into the formula to get P0

9000 = P_0e^{0.1386\times 3}\\9000 = P_0e^{0.4158}\\9000 = 1.5156P_0\\P_0 = \frac{9000}{1.5156}\\ P_0 = 5938.24

Hence the initial population is approximately 5938.

b) In order to know how fast the population growing at t = 10, we will substitute t = 10 into the formula as shown:

P(10) = 5938.24e^{0.1386(10)}\\P(10) = 5938.24e^{1.386}\\P(10) = 5938.24(3.9988)\\P(10) = 23,745.97

Hence the population of the community after 10 years is approximately 23,746

4 0
4 years ago
A circle is drawn within a square as shown.
sleet_krkn [62]

Answer:

The answer is 168.56

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and then find area of circle  

now remove area of circle from area of the square

hope this helps you quickly

Step-by-step explanation:

IT WOULD BE D

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3 years ago
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damaskus [11]
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Convert both to mixed numbers:

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The solution set is -4, -3, -2, -1, 0, 1, 2, 3, 4, 5

I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!

5 0
4 years ago
Solve each inequality. I need help please.
Radda [10]
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3 years ago
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