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Maru [420]
2 years ago
11

In the similar quadrilaterals below, what angle corresponds to ∠C

Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
4 0

Answer:

angle G

Step-by-step explanation:

the quadrilateral did not change position or ration, it only shrank, so all the angles are in the same place and angle C = angle G

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Select the equation of the line to the equation y=-4x-6 and that passes through the point (1,2)
omeli [17]
I don't see a list of options, but I know that the answer is y = -4x + 6.

Point - Slope Form: y - y₁ = m(x - x₁)

y - 2 = -4(x - 1)

y - 2 = -4x + 4
  + 2          + 2
--------------------
y = -4x + 6
7 0
4 years ago
11/ 42 Marks
amm1812

Answer:

(a)x=128 degrees

(b)\angle APD\neq 116^\circ

Step-by-step explanation:

\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ

(a) Now:

\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the  angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ

(b)

\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ

\angle APD\neq 116^\circ

7 0
3 years ago
Essential: Solve the proportions<br> step by step ​
vazorg [7]

Answer:

The value of r=\frac{-106}{47}

The value of x=\frac{83}{32}

Step-by-step explanation:

Given that,

A) \frac{2r-2}{7r+10} = \frac{9}{8}

Now,

\frac{2r-2}{7r+10} = \frac{9}{8}

8(2r-2)=9(7r+10)

16r-16=63r+90

-16-90=63r-16r

-(16+90)=47r

-106=47r

r=\frac{-106}{47}

B) \frac{x+4}{9} = \frac{3(x-2)-1}{5}

Now,

\frac{x+4}{9} = \frac{3(x-2)-1}{5}

5(x+5)=9[3(x-2)-1]

5x+25=9[3x-6-1]

5x+25=9[3x-7]

5x+25=27x-63

25+63=27x+5x

83=32x

x=\frac{83}{32}

6 0
4 years ago
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