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CaHeK987 [17]
2 years ago
14

On a coordinate plane, a dashed straight line has a negative slope and goes through (0, 3) and (2, negative 1). Everything to th

e left of the line is shaded.
Which linear inequality is represented by the graph?

y > 2x + 3
y < 2x + 3
y > −2x + 3
y < −2x + 3
Mathematics
1 answer:
svp [43]2 years ago
5 0

The linear inequality of the given graph is: D. y < -2x + 3.

<h3>How to Determine the Linear Inequality of a Graph?</h3>

First, using two points on the line, (0, 3) and (1.5, 0), find the slope (m).

Slope (m) = change in y / change in x = (3 - 0) / (0 - 1.5)

Slope (m) = 3/-1.5 = -2.

Next, substitute (x, y) = (0, 3) and m = -2 into y = mx + b to find the value of b.

3 = -2(0) + b

3 = 0 + b

b = 3

Substitute m = -2 and b = 3 into y < mx + b (the shaded part is at the left, so we use the "<" sign)

y < -2x + 3

Learn more about inequality graph on:

brainly.com/question/9774970

#SPJ1

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n^2 -  2 n - 3 = 5\\\implies  n^2  -2n - 8  =  0\\\implies  n^2  -4n +  2n - 8  =  0\\\implies n(n-4)  + 2(n-4)  = 0\\\implies (n-4) (n+2)  = 0

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