Answer:
m = 36
Step-by-step explanation:
3 = m/12
Multiply each side by 12
3*12 = m/12*12
36 =m
Answer:
Ty = √k * Tx
The orbital period of Y has to be be multiplied by √k . or . k∧1/2
Step-by-step explanation:
The general equation:
T² = A³
is for the case of planet X
Tₓ² = Aₓ³
In the case of planet Y
Ty² = k * Aₓ³ . and Aₓ³ = Tₓ²
By substitution:
Ty² = k *Tₓ²
Ty = √k * Tx
Answer = 36.0 mph
As per the question,
Actual speed of the car = 40 mph.
Speedometer has a percent error of 10%.
The error can be negative as well as positive.
If the error is negative, it means speedometer is showing less speed than actual speed= - 10%
10 % of 40 = 4
speed shown by speedometer = 40 - (10% of 40) = 36 mph
If the error is positive, it means speedometer is showing more speed than actual speed = +10%
speed shown by speedometer = 40 + ( 10% of 40) = 44 mph
as per the given options, correct option is 36.0 mph
The length = 6W + 7. 2L + 2W = 70. This is a system of equations. To get L by itself in the second problem, -2W from both sides to get 2L = 70 - 2W. Divide by 2 to get L = 35 - W. Now put them together. 6W +7 = 35 - W. Add W to both sides to get 7W + 7 = 35. Subtract 7 from both sides to get 7W = 28. Divide 7 to both sides to get W = 4. Now replace W with 4. 6(4) + 7 = L. 24 + 7 = 31. The length is 31. To check, do the second equation. 2(31) + 2(4) = 62 + 8 = 70. Your answer is 31.
