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3 years ago

What is the area of a parallelogram whose vertices are A(−1, 12) , B(13, 12) , C(2, −5) , and D(−12, −5) ?

1 answer:

8 0

238 square units. The area of a parallelogram is the base multiplied by the height. You can use any of its four sides as the base, so pick the one that is easiest to deal with. Examining the parallelogram, you'll notice that line segments AB and CD are both parallel to the x axis which makes it extremely easy to calculate the height which is 12 - (-5) = 17. The length of AB is 13 - (-1) = 14. So the area of the parallelogram is 14 * 17 = 238

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Answer:

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3 years ago

In a study, 8 people ate a total of 1,312 pounds of potatoes in 2 years.

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1. Divide 1,312 by 2

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3 years ago

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3 years ago

Which is the longer trip from Earth, a one-way trip to Mars or a round-trip to Venus?

dimulka [17.4K]

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3 years ago

Read 2 more answers

If the measure of arc GH= 90° and the measure of arc EF= 45°, calculate m∠GDH.

user100 [1]

Answer:

∠ GDH = 67.5°

Step-by-step explanation:

The measure of the chord- chord angle GDH is half the sum of the measures of the arcs intercepted by the angle and its vertical angle.

∠ GDH = $\frac{1}{2}$ (GH + EF) = $\frac{1}{2}$ (90 + 45)° = 0.5 × 135° = 67.5°

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3 years ago