-7(x-4) = 63. Divide each side by -7.
x - 4 = -9. Add 4 to each side.
x = -5
G(f(x))=? g(x)=2x^2-4? hope this is what you mean
g(f(x))=2(4x+2)^2-4
g(f(x))=2(16x^2+16x+4)-4
g(f(x))=32x^2+32x+8-4
g(f(x))=32x^2+32x+4
Answer
<em>length = width + 15</em>
<em>Area = length * width; area is 54 square feet.</em>
<em>Two equations are:</em>
<em>L = W + 15</em>
<em>L * W = 54</em>
<em>To solve, we substitute first equation into second equation:</em>
<em>(W + 15) * W = 54</em>
<em>w^2 + 15w = 54</em>
<em>w^2 + 15w - 54 = 0</em>
<em>(w+18)(w-3) = 0</em>
<em>w = -18 or 3</em>
<em>The width cannot be negative, so 3 is the width and since length is 15 more than width, length is 18:</em>
<em />
<em>Length = 18 feet</em>
<em>Width = 3 feet</em>
<em />
<em />
Answer:
Answer B
Step-by-step explanation:
x = 0
fx =2*3
f(0)=2
f(1) =6 (1,6)
Answer is Graph B
<em><u>Hope this helps.</u></em>
To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.
Prime factorization of 36=2×2×3×3
Prime factorization of 40=2×2×2×5
Prime factorization of 48=2×2×2×2×3
Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.
720seconds=
60
720
minutes=12minutes
Hence, all the bells will ring together after 12 mi
