What is the solution to this system of linear equations y-x=4 and y+2x=1

Mathematics

1 answer:

DerKrebs [107]3 years ago

8 0

Good luck.............................

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I need help on this problem 20 ÷ (4 - (10 - 8))

vlada-n [284]

Answer: 10

Explanation:

20 ÷ (4- (10-8))

First off, you work your way outward. You start the furthest in, then head your way out. (10 - 8) is the furthest in, and 10 - 8 = 2. So now your equation looks like this:

20 ÷ (4 - 2)

Next, you do the (4 - 2) which equals 2. So now, the equation is this:

20 ÷ 2

So you finish it up with 20 ÷ 2 which equals 10.

Hope I made sense! :D

8 0

4 years ago

Write a equation in the form y=mx+b for the line which contains the points (-8,20) and (-4,0)

marin [14]

M = 20/-4 = -5

Sub in (-4,0): 20+b = 0 ->b = -20

So, y = -5x - 20

3 0

4 years ago

Read 2 more answers

I have a question where I need to add the mixed numbers 5 3\8 and 3 2\5 using a model and number line I have absolutely no idea

VMariaS [17]

Answer:

$8\frac{31}{40}$

Step-by-step explanation:

In representing mixed numbers on a number line, we need first to pay attention to the denominators. Here, denominators are 8 and 5, their least common multiple is 40, so, we will need to cut up space between two numbers on the number line on 40 pieces. Also, we have 5 and 3 wholes at these mixed numbers, so, our answer is going to be greater than 8.

We will cut the space between 8 and 9 on a number line on 40 pieces, and we will add $\frac{3}{8}$ and $\frac{2}{5}$ and get :