All categories

3 years ago

Help me please this is due today

Mathematics

2 answers:

Aneli [31]3 years ago

5 0

Answer:

1. 2

2. 18

Step-by-step explanation:

matrenka [14]3 years ago

4 0

Answer:

LCM = 20, GCF = 9

Step-by-step explanation:

You might be interested in

A construction worker is looking at blueprints drawn to a 1/20 scale and notices that a wall is 0.5 feet by 0.25 feet. He claims

Gnoma [55]

Answer:

incorrect

Step-by-step explanation:

we are finding area which is squared, or we can put it in an equation, (0.5*20)*(0.25*20) or 0.5*0.25*20^2 which equals 50 but (0.5*0.25)*20 only equals 2.5 therefor he is incorrect and the correct answer would be 20^2 or 400 times the area.

hope this helps :)

5 0

3 years ago

Jane needs $20 to buy her radio. She has saved $15.

UNO [17]

Answer: i think it's 75

Step-by-step explanation: because 5 is half of 10 and 10 is half it makes 75

5 0

3 years ago

Select the correct solution set.

Ksju [112]

Answer:

{x | x ≤ -8}

Step-by-step explanation:

-7x ≥ 56

Divide each side by -7, remembering to flip the inequality since we are dividing by a negative

-7x/-7 ≤ 56/-7

x ≤ -8

4 0

3 years ago

Read 2 more answers

Need help on problem 10

Shkiper50 [21]

The Perimeter of Triangle ABC would be 60.
You can solve this by setting up proportions.

3 0

4 years ago

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago