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3 years ago

Help me please this is due today

Mathematics

2 answers:

Aneli [31]3 years ago

5 0

Answer:

1. 2

2. 18

Step-by-step explanation:

matrenka [14]3 years ago

4 0

Answer:

LCM = 20, GCF = 9

Step-by-step explanation:

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Which statements correctly compare two numbers

Katyanochek1 [597]

There are symbols, which have statements.
<,>, and = Greater Than, Lesser Than, and Equal To.

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3 years ago

Read 2 more answers

What is the distance between (-2, 6) and (-2, -1)

Sloan [31]

Answer:

7 units

Step-by-step explanation:

(-2,6)=(X1,Y1)

(-2, -1)=(X2,Y2)

now ,

distance=√{(x2-x1)^2+(y2-y1)^2}

=√{(-2+2)^2+(-1-6)^2}

=√49

=7 units

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3 years ago

sally’s huge dog weighed 175 pounds in 2018 and then weighed 145 pounds in 2020 what is the rate of change and weight?

stiks02 [169]

Answer:17.14%

Step-by-step explanation:

145 x

_____=_____

175 100

145(100)=175(x)

14500=175x

__________

175 175

x=82.86

100-82.86=17.14%

7 0

3 years ago

A new anxiety medication has been manufactured and a study is being conducted to determine whether its effectiveness depends on

Irina18 [472]

The test statistics is used to determine if the anxiety medication can happen under a null hypothesis

The test statistics that is an appropriate hypothesis test is $z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}$

<h3>How to determine the test statistic</h3>

<u>40 milligrams of medication</u>

Patients = 60

Lower stress level patients = 21

The mean of this medication is:

$\bar x = \frac{x}{n}$

So, we have:

$\bar x_1 = \frac{21}{60}$

$\bar x_1 = 0.35$

<u>75 milligrams of medication</u>

Patients = 85

Lower stress level patients = 34

The mean of this medication is:

$\bar x = \frac{x}{n}$

So, we have:

$\bar x_2 = \frac{34}{85}$

$\bar x_2 =0.4$

The test statistic is then calculated as:

$z =\frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\bar x_1(1 - \bar x_1)}{n_1} + \frac{\bar x_2(1 - \bar x_2)}{n_2}}}$

The equation becomes

$z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}$

Hence, the test statistics that is an appropriate hypothesis test is $z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}$