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iren [92.7K]
2 years ago
12

A cylindrical pain can has a diameter of 12 centimeters and height of centimetrs which is closest to the volume of the paint can

in cubic centimeters
Mathematics
1 answer:
Karolina [17]2 years ago
4 0

The volume of the cylinder having diameter 12 cm and height of 4 cm is 452 cm^{3}.

Given diameter of cylinder be 12 cm and height of cylinder be 4cm.

We are required to find the volume of cylinder.

Volume is the quantity of substance a container can hold in its capacity.

Diameter=12 cm

Radius=6 cm (Radius is always equal to half of diameter)

Volume of cylinder=πr^{2} h

We have to just put the values of r, h and π in the formula to get the volume of the cylinder.

Volume=π(6)^{2} 4

=3.14*4*36

=452.57 cm^{3}

After rounding off we will get 452 cm^{3}.

Hence the volume of cylinder is 452 cm^{3}.

Learn more about volume at brainly.com/question/463363

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Question is incomplete as it should include height of cylinder be 4cm.

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Find the measure of one interior angle for the following regular polygon
shusha [124]

Answer:

Step-by-step explanation:

I am assuming that by "interior" angle you do not mean the central angle.

This is a 10-sided polygon, a decagon. That means that there are 10 triangles that can extend from the center, with their sides being equal to the radii of the decagon. If we extract one of these triangles we can find what the interior angle is. The vertex angle measures 360/10 which is 36.

Split this triangle in half from the vertex to the base, creating a right triangle. The vertex angle is also split in half, making this angle (the vertex angle is the one at the top of the triangle) 18 degrees. We already know that one angle inside this right triangle is 90 (definition of a right triangle) and to find the other one, we apply the Triangle Angle-Sum Theorem:

180 - 18 - 90 = 72 degrees. That is the measure of the base angle that is NOT the right angle, obviously.

4 0
3 years ago
Find the length of the right triangle’s other leg. Round to the nearest tenth. SHOW YOUR WORK. leg = 9 ft hypotenuse = 12 ft
GREYUIT [131]

Use the Pythagorean Theorem: a^2 + b^2 = c^2. a and b are the legs, and c is the hypotenuse. Plug in your numbers: 9^2 + b^2 = 12^2

81 + b^2 = 144. Subtract 81 from 144 : b^2 = 63. Now take the square root of 63, which is 7.9. 7.9 ft is your answer.

3 0
3 years ago
Evaluate the expression for x = 3, y = 1/3 , and z = 5.<br><br>12x − 3y / 4x − z​
DIA [1.3K]

Step-by-step explanation:

<u>Substitute the given values into the expression;</u>

12(3) - 3( \frac{1}{3} ) \div 4(3) - 5

<u>Multiply;</u>

36 - 1 \div 12 - 5

<u>Solve Using PEMDAS;</u>

36 -  \frac{1}{12}  - 5

35 \frac{11}{12}  - 5

\boxed{30 \frac{11}{12} }

4 0
2 years ago
Their mother measures their shadows.Dixon's shadow is 9 feet long and Ariadne's shadow is feet long. If Dixon is 6 feet tall, ho
Shalnov [3]

Dixon is 6 feet tall,  Ariadne is 4 feet tall by proportion.

What in mathematics is a proportion?

  • A proportion is an equation that sets two ratios at the same value.
  • For instance, you could express the ratio as follows: 1: 3 if there is 1 boy and 3 girls (for every one boy there are 3 girls) There are 1 in 4 boys and 3 in 4 girls. 0.25 are male (by dividing 1 by 4)

We can use the proportion.

We already know that Dixon is 6 ft tall and that his shadow is 9 ft long.

Also we know that the shadow of his sister is 6 ft long.

6 : x = 9 : 6, or 6 / x = 9 / 6.

After that we will cross multiply : 9 * x = 6 * 6,

9 x = 36 ,

x = 36 /9,

x = 4.

Ariadne is 4 feet tall.

Learn more about proportion

brainly.com/question/2548537

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The complete question is -

Dixon and his little sister Ariadne stand next to each other on the playground on a sunny afternoon. Their mother measures their shadows. Dixon's shadow is 9 feet long and Ariadne's shadow is 6 feet long. If Dixon is 6 feet tall, how tall is Ariadne?

6 0
1 year ago
If the cube shown is 5 inches on all sides, what is the length of the diagonal, x, of the cube?
Pavel [41]

Answer:

5\sqrt{3} inches

Step-by-step explanation:

3 0
3 years ago
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