All categories

3 years ago

Find the length of the right triangle’s other leg. Round to the nearest tenth. SHOW YOUR WORK. leg = 9 ft hypotenuse = 12 ft

1 answer:

3 0

Use the Pythagorean Theorem: a^2 + b^2 = c^2. a and b are the legs, and c is the hypotenuse. Plug in your numbers: 9^2 + b^2 = 12^2

81 + b^2 = 144. Subtract 81 from 144 : b^2 = 63. Now take the square root of 63, which is 7.9. 7.9 ft is your answer.

You might be interested in

9^2 - (4) (2) (-6) what is the answer?

Rus_ich [418]

Answer:

129

Step-by-step explanation:

pls heart and give brainliest much appreciated

4 0

3 years ago

4cos(10x)+2=2<br><br> What would this equal in Degrees??

Ipatiy [6.2K]

Answer:

Simplifying

4cos(10x) + 2 = 2

Remove parenthesis around (10x)

4cos * 10x + 2 = 2

Reorder the terms for easier multiplication:

4 * 10cos * x + 2 = 2

Multiply 4 * 10

40cos * x + 2 = 2

Multiply cos * x

40cosx + 2 = 2

Reorder the terms:

2 + 40cosx = 2

Add '-2' to each side of the equation.

2 + -2 + 40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

0 + 40cosx = 2 + -2

40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

40cosx = 0

Solving

40cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '40'.

cosx = 0.0

Simplifying

cosx = 0.0

The solution to this equation could not be determined.

Step-by-step explanation:

7 0

4 years ago

What is the slope of the line that passes through the points (5, 0) and (10, 0)

Ierofanga [76]

Answer:

The slope is zero

Step-by-step explanation:

We can find the slope of a line given two points by using

m = (y2-y1)/(x2-x1)

= (0-0)/(10-5)

= 0/5

7 0

4 years ago

You multiply two integers. You increase one of them by 1 and decrease the other

snow_tiger [21]

Integers are numbers without decimals

The integers could you have multiplied are 9 and 2

Let the numbers be x and y

So, we have:

$\mathbf{x \times y}$

Increase x by 1 and reduce y by 1.

So, we have

$\mathbf{(x +1) \times (y -1) = 6 + xy }$

Open brackets

$\mathbf{xy -x + y - 1 = 6 + xy}$

Subtract xy from both sides

$\mathbf{ -x + y - 1 = 6}$

Collect like terms

$\mathbf{ -x + y = 6 + 1}$

$\mathbf{ -x + y = 7}$

Rewrite as:

$\mathbf{ y -x= 7}$

The above means that, the difference between the integers is 7.

There are several integers that fit the above <em>description</em>;

One possibility is: 9 and 2