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Sunny_sXe [5.5K]
2 years ago
11

A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon‐hy

drogen bonds in a CH4 molecule.
Chemistry
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

The methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.

The complete question is:

<em>For each of the following situations, you are asked which of two objects or substances has the higher energy. Explain your answer with reference to the capacity of each to do work and say whether the energy that distinguishes them is kinetic energy or potential energy.</em>

<em>a. (1) A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon-hydrogen bonds in a CH4 molecule.</em>

<h3>Which have a higher energy?</h3>

The methane molecule in the stratosphere is a stable molecule and possesses chemical potential energy.

The CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule are unstable molecules and possesses kinetic energy. However, some of their energy has been used in breaking the bond.

Thus, the methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.

In conclusion, the energy in the methane molecule is higher.

Learn more about potential energy at: brainly.com/question/14427111

#SPJ1

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3 years ago
Draw the structure for 1-nitrobutane, making sure to add all non-zero formal charges.
TiliK225 [7]

The molecular structure of 1-nitrobutane is C_{4} H_{9} NO_{2}. The structure of 1-nitrobutane is shown below.

An atom's formal charge would be determined by the covalent model of chemical bonding, which assumes that almost all chemical bonds include equal sharing of electrons among all atoms, regardless their relative electronegativity.

The structure for 1-nitrobutane, making sure to add all non-zero formal charges

There are four kind of molecule present in 1-nitrobutane and they are carbon, hydrogen , nitrogen and oxygen. Nitrogen is bonded with two oxygen atom out of them one oxygen atom is attached with single bond and second oxygen atom is bonded with double bond. Nitrogen has positive charge whereas oxygen has negative charge.

It is a kind of alkane in with nitro group is attached with alkane group.

To know more about 1-nitrobutane

brainly.com/question/25045923

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7 0
2 years ago
For salt formation procedure crude lidocaine should be dissolved in diethyl ether and 2 ml of 2.2 M sulfuric acid should be adde
mixas84 [53]

Answer:

20 equivalents of sulfuric acid are needed to per equivalent of lidocaine.

Explanation:

To do this calculation we should take in account the key information given:

<em>2 mL (0.02 L) of sulfuric acid (H2SO4) 2.2 M per 1 g of lidocaine (molecular weight=234.34 g/mol)</em>

So we can calculate from here the number of moles of each compound needed for the procedure.

Starting with the sulfuric acid, we know that the molar concentration is defined as [concentration] =n(moles number)/V(volume).

So n=[concentration]*V, and therefore :

n(H2SO4)=2.2 M * 0.02 L=0.044 mol

While the moles of lidocaine can be calculated as n(moles number)=m(mass amount)/mW(molecular weight), so:

n(lidocaine)=m(lidocaine)/mW(lidocaine)= 1 g /234,34 g/mol~0,0043 mol.

Now we can calculate the equivalents.

Take in account that for sulfuric acid, de number of equivalents per mole is 2 (because of the double dissociation of the acid), while the number of equivalents per mole of lidocaine is 1.

Then we can conclude that:

0,0043 equivalents of lidocaine need 0,088 equivalents of sulfuric acid

1 equivalent of lidocaine need (0,088/0.0043)=20,46~20 equivalents of sulfuric acid

Finally, we can conclude that for the described procedure, 20 equivalents of sulfuric acid per equivalent of lidocaine are needed.

4 0
3 years ago
Compare 1 mole of H2, 1 mole of O2 and 1 mole of F2
likoan [24]

Explanation:

(a)  As per the mole concept, one mole of any atom contains 6.022 \times 10^{23} atoms or molecules, that is, Avogadro's number of atoms.

Therefore, 1 mole of H_{2} = 2 \times 6.022 \times 10^{23} molecules

                                           = 1.2044 \times 10^{23} molecules

   1 mole of O_{2} = 2 \times 6.022 \times 10^{23} molecules

                                    = 1.2044 \times 10^{23} molecules

   1 mole of F_{2} = 2 \times 6.022 \times 10^{23} molecules

                                    = 1.2044 \times 10^{23} molecules

Hence, there are equal number of molecules present in the given atoms.

(b)   Mass of each given atom will be calculated as follows.

                Mass = no. of moles × molar mass

As one molecule of H_{2} contains 2 atoms of hydrogen.

So, mass of 1 mole of H_{2} = 2 mol \times 1.008 g/mol

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      mass of 1 mole of O_{2} = 2 mol \times 15.999 g/mol

                                                     = 31.996 g

      mass of 1 mole of F_{2} = 2 mol \times 18.998 g/mol

                                                     = 37.996 g

Thus, we can conclude that F_{2} has the greatest mass.

8 0
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CaHeK987 [17]

Answer:

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Explanation:

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