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tatuchka [14]
2 years ago
13

How many grams of butane were in 1. 000 atm of gas at room temperature?

Chemistry
1 answer:
dimaraw [331]2 years ago
3 0

The mass in grams of butane at standard room temperature is 53.21 grams.

<h3>How can we determine the mass of an organic substance at room temperature?</h3>

The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:

PV = nRT

  • Pressure = 1.00 atm
  • Volume = 22.4 L
  • Rate = 0.0821 atm*L/mol*K
  • Temperature = 25° C = 298 k

1 × 22.4 L = n × (0.0821 atm*L/mol*K×  298 K)

n = 22.4/24.4658 moles

n = 0.91556 moles

Recall that:

  • number of moles = mass(in grams)/molar mass

mass of butane = 0.91556 moles × 58.12 g/mole

mass of butane = 53.21 grams

Learn more about calculating the mass of an organic substance here:

brainly.com/question/14686462

#SPJ12

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Answer:

131 atm

Explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm                       P₂ = ? atm

V₁ = 7.74 L                           V₂ = 0.23 L

P₁V₁ = P₂V₂                                                      <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L)                       <----- Insert values

30.0312 = P₂(0.23 L)                                      <----- Simplify left side

131 = P₂                                                          <----- Divide both sides by 0.23

6 0
2 years ago
Name this compound [TiBr3(NMe3)3]
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5 0
3 years ago
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5 0
3 years ago
An atom of gold has a mass of 3.271 x 10-22g. How many atoms of gold are in 5.00g of gold?
rosijanka [135]
To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation  \frac{mass of gold}{mass of gold atom}. 

Let x be the number of gold atoms. Plug in the values to a calculator.

x = \frac{5.00g}{3.271 x 10-22g}
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3 0
4 years ago
Fe2O3+2Al=Al2O3+2Fe
True [87]
We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
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= 1.17
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6 0
3 years ago
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