Answer:
<h2>
perimeter of △SMP = 25</h2>
Step-by-step explanation:
The perimeter of the triangle △SMP is the sum of al the sides of the triangle.
Perimeter of △SMP = ||MS|| + ||MP|| + ||SP||
Note that the triangle △LRN, △LSM, △MPN and △SRP are all scalene triangles showing that their sides are different.
Given LM=9, NR=16 and SR=8
NR = NP+PR
Since NP = PR
NR = NP+NP
NR =2NP
NP = NR/2 = 16/2
NP = 8
From △LSM, NP = PR = <u>MS</u><u> = 8</u>
Also since LM = MN, MN = 9
From △SRP, SR = RP = <u>PS = 9</u>
Also SR =<u> MP = 8</u>
From the equation above, perimeter of △SMP = ||MS|| + ||MP|| + ||SP||
perimeter of △SMP = 8+8+9
perimeter of △SMP = 25
Answer:
Wyatt wrote the correct expression
Step-by-step explanation:
Here we are to evaluate which of the students wrote an expression with the highest common factor being 8c
For Tanya; 32c + 16c; 16c( 2 + 1); This is wrong as the highest common factor is 16c
For Wyatt, we have 8c - 48cd; factorizing, we have 8c(1-6cd); This is correct
For Xavier we have 36c-24c; 8 is not a factor of 36, so it won’t work
For Yang 8c + 40; 8(c+ 5); what we are trying to look for is 8c and not 8 so this is wrong also
The exponential function that describes the graph is 
The standard form of an exponential function is expressed as 
a is the y-intercept
(x, y) is the point on the graph
Given the following expression
a = 7
(x, y) = (4, 112)
Substitute the given values into the exponential equation
![y = ab^x\\112=7\cdot b^4\\b^4 = \frac{112}{7}\\b^4= 16\\b =\sqrt[4]{16}\\b = 2](https://tex.z-dn.net/?f=y%20%3D%20ab%5Ex%5C%5C112%3D7%5Ccdot%20b%5E4%5C%5Cb%5E4%20%3D%20%5Cfrac%7B112%7D%7B7%7D%5C%5Cb%5E4%3D%2016%5C%5Cb%20%3D%5Csqrt%5B4%5D%7B16%7D%5C%5Cb%20%3D%202)
Get the required exponential equation
Recall that
, hence the required equation will be 
Learn more here: brainly.com/question/19245707
Its B
Hope this helps!
May I have brainliest please? :D
The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥. The half-plane that is a solution to the inequality is usually shaded.
Example:
Is (1, 2) a solution to the inequality
2x+3y>1
2times1+3times2>1
2+5>1
7>1