Just completed this question as of right now it’s was : “ a common ratio between 0 and 1
Answer:
x = 10
Step-by-step explanation:
2x/3 + 1 = 7x/15 + 3
<em><u>(times everything in the equation by 3 to get rid of the first fraction)</u></em>
2x + 3 = 21x/15 + 9
<em><u>(times everything in the equation by 15 to get rid of the second fraction)</u></em>
30x+ 45 = 21x + 135
<em><u>(subtract 21x from 30x; subtract 45 from 135)</u></em>
9x = 90
<em><u>(divide 90 by 9)</u></em>
x = 10
<h2>
Another solution:</h2>
2x/3 + 1 = 7x/15 + 3
<u><em>(find the LCM of 3 and 15 = 15)</em></u>
<u><em>(multiply everything in the equation by 15, then simplify)</em></u>
10x + 15 = 7x + 45
<u><em>(subtract 7x from 10x; subtract 15 from 45)</em></u>
3x = 30
<em><u>(divide 30 by 3)</u></em>
x = 10
Answer:

Step-by-step explanation:
So we have the equation:

And we want to solve for g.
First, isolate g. To do so, subtract vt from both sides:

Multiply both sides by 2:

Now, divide both sides by t^2:

Expand:

Simplify the second term:

And we're done!
Answer:
x=15
Step-by-step explanation:
21:2x=7:10 can be rewritten as 21/2x=7/10
21/2x=7/10, cross multiply
= 14x=210
x=15

Divide both the numerator and denominator by 9 to get;

Convert the improper fraction to a mixed number;