Question

Andy is collecting pocket change for a fundraiser. he begins with 102 coins in the cup, and their monetary value is $17.10. if he has a mix of dimes and quarters, how many of the coins are dimes?

Answer 1

If Andy has 102 coins mixed with dimes and quarters and monetary value of $17.10 then he has 56 dimes and 42 quarters.

Given number of coins Andy has is 102 and montary value of all coins is $17.10.

We have to determine number of dimes and quarters.

1 dime=$0.10

1 quarter=$0.25

Suppose the number of dimes be x and number of quarters be y.

The equations are:

0.10x+0.25y=17.10------------1

x+y=102-------------2

from equation 2, y=102-x

Put the value of y=102-x in equation 1

0.10x+0.25(102-x)=17.10

0.10x+25.5-0.25x=17.10

-0.15x=17.10-25.5

-0.15x=-8.4

x=8.4/0.15

x=56

Put the value of x in y=102-x

y=102-56

y=46

Hence Andy has 56 number of dimes and 46 quarters.

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