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dexar [7]
2 years ago
9

What is the asset turnover?

Mathematics
2 answers:
julia-pushkina [17]2 years ago
6 0

Answer:

Days of Asset Turnover The Enterprise Accounting System specifies that the net revenue from main business of an enterprise should be the amount of revenue from main business after deducting sales discounts and sales discounts, which is called net revenue from main business. Total asset turnover ratio = total sales revenue / average total assets x 100%.

Step-by-step explanation:

tekilochka [14]2 years ago
4 0

Answer:

the ratio of total sales or revenue to average assets

Step-by-step explanation:

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The value of √30 is between which two to numbers ?
Naddika [18.5K]
5 and 6, the value is about 5.48
8 0
4 years ago
Mrs. Smith left a 15% tip for a dinner that cost $62.40. About how much tip did Mrs. Smith leave?​
Veronika [31]

<u>Given </u><u>:</u><u>-</u><u> </u>

  • Mrs. Smith left a 15% tip for a dinner that cost $62.40.

<u>To </u><u>find</u><u> </u><u>:</u><u>-</u><u> </u>

  • About how much tip did Mrs. Smith leave?

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

The tip is 15% of $62.40 .

<u>•</u><u> </u><u>Calculating</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>of </u><u>$</u><u>6</u><u>2</u><u>.</u><u>4</u><u>0</u><u> </u>

  • $ 62.40 * 15%
  • $ 62.40 * 15/100
  • $ 9.36
4 0
3 years ago
Read 2 more answers
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
3 years ago
The following table shows the length and width of two rectangles:
faltersainse [42]
The perimeter of these can be found by adding length and width and then multiplying by two. 

Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2 
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4x + 14
So rectangle A's perimeter is 4x + 14.

Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6

And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8

So it would be C.
5 0
4 years ago
Whats the property? If -7x=14 then 14=-7x
timofeeve [1]

Answer:

the answer is commutative property

Step-by-step explanation:

commutative property is when both constants or variables don't change value when you move them from one side of the equal sign to another such as "a+b = b+a" or " a=b; b=a" both examples do not change value

3 0
3 years ago
Read 2 more answers
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