Answer:
Multiply the top equation by -3 and the bottom equation by 2
Step-by-step explanation:
Given <u>system of equations</u>:

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>. To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.
<u>To eliminate the </u><u>variable y</u>:
Multiply the top equation by -3 to make the coefficient of the y variable 6:

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

Add the two equations together to <u>eliminate y</u>:

<u>Solve</u> for x:


<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:





Learn more about systems of equations here:
brainly.com/question/27868564
brainly.com/question/27520807
Answer:
Option b is correct 175
Step-by-step explanation:
n = 7
k = 6
3k -2 ------1
put k = 6 in above eq. for finding first term
a1 = 3(6) - 2 = 18 - 2 = 16
put k = 7 in above eq. for finding first term
a2 = 3(7) - 2 = 21 - 2 = 19
a3 = 3 (8) - 2 = 24 - 2 = 22
16, 19 , 22, ... //Arithmetic series formation
a1 = 16 , a2 = 19
d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms
Using sum forumula for arithmetic series
sum = 
= 
= 
=
=
= 7 * 25
= 175
Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.