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3 years ago

14

Identify the error in each problem. Explain each error and provide the correction solution. Use at least two complete sentences.

PLEASE SOMEONE HELP QUICK ITS DUE TOMORROW AND I WILL MARK YOU BRAINLIEST

1 answer:

mariarad [96]3 years ago

4 0

Answer:

the mistake is the addition sign. When a number is next to a parenthesis it means multiplication

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Nonamiya [84]

450 multiplied by .025 also known as 2.5 percent which equals 11.25 dollars
which is her commission for the week

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3 years ago

0843+0711 military time

Rashid [163]

Answer: 22 hours 28 minutes

Step-by-step explanation: 0843 means 8:43am and 0711 means 7:11am military time. In that order there is 22 hours 28 minutes from 8:43am today to 7:11 am tomorrow. The question itself is rather confusing so if this is not what you meant please let me know and I will re-do it.

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4 years ago

A. State the coordinates of each point and in which quadrant they lie.

olga_2 [115]

Answer:

a)

I (1, 2) quadrant 1
J (3, -1) quadrant 4
K (-4, 0) x-axis
L (-4, 2) quadrant 2
M (4, -4) quadrant 4

b) (-4, 0)

c) (4, 2)

d) (-3, 1)

Step-by-step explanation:

a)

I (1, 2) quadrant 1
J (3, -1) quadrant 4
K (-4, 0) x-axis
L (-4, 2) quadrant 2
M (4, -4) quadrant 4

b) (-4, 0) doesn't move as it is already on the x-axis

c) (4, 2)

d) (-3, 1)

reflected in the x-axis = (3, 1), then reflected in the y-axis = (-3, 1)

8 0

3 years ago

HELP QUICK THIS IS DUE IN FIVE MINUTES!!!!!

Komok [63]

2 x (5-2)^3
2 x (3)^3
2 x 27
54

8 0

3 years ago

Read 2 more answers

Let divf = 6(5 − x) and 0 ≤ a, b, c ≤ 12. (a) find the flux of f out of the rectangular solid 0 ≤ x ≤ a, 0 ≤ y ≤ b, and 0 ≤ z ≤

dusya [7]

Continuing from the setup in the question linked above (and using the same symbols/variables), we have

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}(\nabla\cdot f)\,\mathrm dV$
$=\displaystyle6\int_{z=0}^{z=c}\int_{y=0}^{y=b}\int_{x=0}^{x=a}(5-x)\,\mathrm dx\,\mathrm dy\,\mathrm dz$
$=\displaystyle6bc\int_0^a(5-x)\,\mathrm dx$
$=6bc\left(5a-\dfrac{a^2}2\right)=3abc(10-a)$

The next part of the question asks to maximize this result - our target function which we'll call $g(a,b,c)=3abc(10-a)$ - subject to $0\le a,b,c\le12$ .

We can see that $g$ is quadratic in $a$ , so let's complete the square.

$g(a,b,c)=-3bc(a^2-10a+25-25)=3bc(25-(a-5)^2)$

Since $b,c$ are non-negative, it stands to reason that the total product will be maximized if $a-5$ vanishes because $25-(a-5)^2$ is a parabola with its vertex (a maximum) at (5, 25). Setting $a=5$ , it's clear that the maximum of $g$ will then be attained when $b,c$ are largest, so the largest flux will be attained at $(a,b,c)=(5,12,12)$ , which gives a flux of 10,800.

7 0

3 years ago