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Crank
2 years ago
11

HELP ASAP!!! 40 POINTS

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
8 0

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

m = f^{\prime}(x_0).

In this problem, the function is:

f(x) = 0.2x^2 + 5x - 12

Hence the derivative is:

f^{\prime}(x) = 0.4x + 5

For a slope of -1, we have that:

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that:

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence the interval is:

(-15,-10).

More can be learned about derivatives and tangent lines at brainly.com/question/8174665

#SPJ1

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