The absolute value of a real number a is a when a≥0, or -a when a<0. The absolute value of -6 is 6. The absolute value of 4 is 4.
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I wont solve this because Im to lazy, but I do recommend some of these sites to help you with your problem. MathPapa Algebra Calculator and PhotoMath. Hope this helps.
The answer to this question would be B, -3. The reason for this is because when you have an equation in slope intercept form, it would be y = mx + b. In this case your b is equal to 0 so you have only y = mx. The variable m represents the slope, which is in this case, equal to -3. Hope this helps. Please rate, leave a thanks, and mark a brainiest answer. (Not necessarily mine). Thanks, it really helps! :D
The answer is: " x < -3 " .
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Explanation:
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Given:
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" 9(2x + 1) < 9x – 18 " ;
First , factor out a "9" in the expression on the right-hand side of the inequality:
9x – 18 = 9(x – 2) ;
and rewrite the inequality:
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9(2x + 1) < 9(x – 2) ;
Now, divide EACH SIDE of the inequality by "9" ;
[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;
to get:
2x + 1 < x – 2 ;
Now, subtract "x" and add "2" to each side of the inequality:
2x + 1 – x + 2 < x – 2 – x + 2 ;
to get:
x + 3 < 0 ;
Subtract "3" from EACH SIDE ;
x + 3 – 3 < 0 – 3 ;
to get:
" x < -3 " .
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