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Black_prince [1.1K]
4 years ago
5

What is the equation of the line shown below?

Mathematics
1 answer:
miskamm [114]4 years ago
7 0

Answer:

y= 1x - 1

Step-by-step explanation:

Slope-intercept form: y=mx + b

(-4,-5) (5,4)

m= (y2 - y1)/(x2 - x1) = (4+5)/(5+4)=1

4=1(5)+b

4=5 + b    4-5=b    b= -1

y= 1x - 1

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The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

The equation is given as: \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

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Read more about roots of an equation at:

brainly.com/question/12912962

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