Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>
Answer:
-83/51
Step-by-step explanation:
i used an app called Symbolab that solves any math problem for u
It's really important that you aim to understand how to do these problems yourself, rather than "pay" others to do them for you. Why not ask for "directions" or "guidance," instead of for "answers?"
This is a tricky question because it's not required that you have the full 12 beads on the string in every case. You could, for example, have 6 beads, 2 of which would be red, making the ratio of red beads 2 to 6, or 1 to 3.
What about 3 red beads in 9?
What about 1 red bead in 3?
Do these "answers" satisfy the requirement that the ratio of red beads to all beads is 1:3?
Answer:
The standard deviation will remain unchanged.
Step-by-step explanation:
Given
Solving (a): The range
This is calculated as:
Where:
So:
Solving (b): The variance
First, we calculate the mean
The variance is calculated as:
So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)
Solving (c): The standard deviation
This is calculated as:
--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
