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3 years ago

2x=2(x-3) solve equation

Mathematics

2 answers:

vagabundo [1.1K]3 years ago

7 0

Well, by doing the work and trying to solve this equation, i have came to the terms that it is a no solution problem

kati45 [8]3 years ago

4 0

2x = 2(x - 3)
2x = 2(x) - 2(3)
2x = 2x - 6
2 2
x = x - 3
- x - x
0 ≠ -3

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What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?

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Answer:

The center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

here,

r = raduis

center = (a, b)

Given the equation

$\left(x-14\right)^2+\left(y+21\right)^2=64$

$\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}$

$\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2$

comparing with the circle equation

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

Therefore, the center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

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Lyrx [107]

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Write the following equation in the general form ax by c = 0. y - x - 1 = 0

Elena-2011 [213]

If you would like to write y - x - 1 = 0 in the general form, you can do this using the following steps:

The general form of the equation is: ax + by + c = 0.

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The correct result would be <span>-x - y - 1 = 0</span>.

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Step-by-step explanation:

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