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2 years ago

2x=2(x-3) solve equation

Mathematics

2 answers:

vagabundo [1.1K]2 years ago

7 0

Well, by doing the work and trying to solve this equation, i have came to the terms that it is a no solution problem

kati45 [8]2 years ago

4 0

2x = 2(x - 3)
2x = 2(x) - 2(3)
2x = 2x - 6
2 2
x = x - 3
- x - x
0 ≠ -3

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How to find 62%of $400

gayaneshka [121]

Answer:

248

Step-by-step explanation:

Solution for What is 400 percent of 62:

400 percent *62 =

(400:100)*62 =

(400*62):100 =

24800:100 = 248

Now we have: 400 percent of 62 = 248

Question: What is 400 percent of 62?

Percentage solution with steps:

Step 1: Our output value is 62.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$62=100\%.

Step 4: Similarly, x=400\%.

Step 5: This results in a pair of simple equations:

62=100\%(1).

x=400\%(2).

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

\frac{62}{x}=\frac{100\%}{400\%}

Step 7: Again, the reciprocal of both sides gives

\frac{x}{62}=\frac{400}{100}

\Rightarrow x=248

Therefore, 400 of 62 is 248

5 0

3 years ago

Read 2 more answers

Jennifer has run many marathons and keeps track of all of her finishing times. At a marathon last month, she finished in 350 min

suter [353]

Answer:

16%

Step-by-step explanation:

406 / 350 = 1.16

406 is 116% of 350

so 350 + 16% is 406

because 350 * 0.16 = 56

56 is 16%

350 + 56 = 406

3 0

2 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .