Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.
Let x be the height of the flagpole, then
Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
The answer is 56.
I know this because...
<span>-6 + {14 + 2 [60 − 9(1 + 3)]}
-6 + </span>{14 + 2[60 − 9(4)]}
-6 + {14 + 2[60 − 36]}
-6 + {14 + 2[24]}
-6 + {14 + 48}
-6 + {62}
-6 + 62 = 56
Answer:
9x^2-49
Step-by-step explanation:
FOIL
Answer:
g(x) = - x² - 4 ⇒ A
Step-by-step explanation:
Let us revise the reflection and translation of a function
- If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
- If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)
- If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)
- If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)
- If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k
- If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) – k
f(x) = x² is the blue curve
g(x) is its image is the red curve
∵ g(x) is the image of f(x)
∵ f(x) is opened upward
∵ g(x) is opened downward
→ That means the sign of y-coordinates of all points on the blue
graph are opposite
∴ f(x) is reflected about the x-axis
∴ Its image is - f(x)
∵ The vertex of f(x) is (0, 0)
∵ The vertex of g(x) = (0, -4)
→ That means the function translated 4 units down
∴ - f(x) is translated 4 units down
∴ Its image is - f(x) - 4
∴ g(x) = - f(x) - 4
∵ f(x) = x²
∴ g(x) = - x² - 4
Fifth root of x is x^1/5 as an exponential expression. . This to the 7th power is
x ^(1/5 * 7) which is x^(7/5). Bringing this to the third power is x^ (21/5) which is your answer.
