Question

A triangular pyramid has a base with an area of 43 cm squared and lateral faces with bases of 10 cm and heights of 8.6 cm. What is the surface area of the pyramid?

Answer 1

Answer:

The total surface area of triangular pyramid is 172 cm squared

Step-by-step explanation:

Triangular pyramid:

• Number of faces 4.
• Number of vertices of a triangular pyramid is 6.
• The volume  is $\frac13 AH$. A= area of the pyramid's base and H= height of the pyramid.

• The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.

Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.

The 3 sides of the triangular pyramid is triangle in shape.

The area of triangle is $\frac12 \times base \times height$.

The lateral surface area of the triangular pyramid is

$=3(\frac12 \times base \times height)$

$=3(\frac12\times 10\times8.6)$ cm squared

=129 cm squared

The total surface area of triangular pyramid is

=Area of the base + lateral surface area

=(43+129) cm squared

=172  cm squared