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PolarNik [594]
1 year ago
5

Draw an area model to represent 4x^2+12x+9 = (2x+3)^2. Label the length and width of the whole square and label each individual

small square and rectangle.
Mathematics
1 answer:
My name is Ann [436]1 year ago
7 0

See attachment for the area model of the equation 4x^2+12x+9 = (2x+3)^2

<h3>What are area models?</h3>

Area models are shapes used to model or illustrate products, multiplications, divisions and quotients

<h3>How to draw the area model?</h3>

The equation is given as:

4x^2+12x+9 = (2x+3)^2

Express (2x+3)^2 as the product of (2x+3) and (2x+3)

4x^2+12x+9 = (2x+3) * (2x+3)

The above means that the area model is a square.

So, the side lengths of the model must be equal, where the side lengths are 2x + 3 and the area of the square is 4x^2+12x+9

See attachment for the area model of the equation 4x^2+12x+9 = (2x+3)^2

Read more about area models at:

brainly.com/question/12245811

#SPJ1

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3 years ago
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A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
Find the perimeter and the area of each shape. Give your answer as a completely simplified exact value in terms of π (no approxi
nydimaria [60]

Answer:

Circumference: 12π + 8 cm,

Area: 48 ( cm )^2

Step-by-step explanation:

This figure is composed of circles, squares, and semicircles. As you can see, the squares indicate that each semicircle should have ( 1 ) the same area, and ( 2 ) the same length ( circumference ). It would be easier to take the circumference of the figure first, as it is composed of arcs part of semicircles the same length.

Circumference of 1 semicircle = \frac{1}{2}( πd ) =  \frac{1}{2}π( 4 ) = 2π ( cm )

Circumference of Figure (composed of 6 semicircles + 2 sides of a square),

We know that 6 semicircles should be 6 * 2π, and as the sides of a square are equal - if one side is 4 cm, the other 3 are 4 cm as well. Therefore the " 2 sides of a square " should be 2

Circumference of Figure = 6 * 2π + 2 = 12π + 8 ( cm )

_____________

The area of this figure is our next target. As you can see, it is composed of 3 semicircles, and the area of 3 semicircles subtracted from the area of 3 squares. Therefore, let us calculate the area of 1 semicircle, and the area of 1 square first.

Area of 1 semicircle = 1/2πr^2 = 1/2π(2)^2 = 2π ( cm ),

Area of 1 square = ( 4 cm )( 4 cm ) = 16 ( cm^2 )

So, the area of the figure should be the following -

Area of Figure = 3 * 2π + 3( 16 - 2π ) = 48 ( cm )^2

3 0
3 years ago
What is the quotient of 4.38 and 0.5
barxatty [35]

4.38 / 0.5 = 8.76

Hope it helps :D

3 0
3 years ago
rachel is frosting the top of two cakes and wants to know which cake will require more frosting. one cake is round with a diamet
siniylev [52]

Answer:

The square cake is larger by 31 in^2

Step-by-step explanation:

A round cake has a circular area on top.

We need to find the radius

d= 2r

8 = 2r

r=4

The area of the circle is pi r^2

A = 3.14 * 4^2

A = 3.14 *16

   = 50.24

The area of the square cake is

A =s^2

A = 9^2

A = 81

The square cake is larger

The difference is Asquare - A round

81 -50.24

30.76

Which is close to 31 in ^2

7 0
3 years ago
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