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PolarNik [594]
1 year ago
5

Draw an area model to represent 4x^2+12x+9 = (2x+3)^2. Label the length and width of the whole square and label each individual

small square and rectangle.
Mathematics
1 answer:
My name is Ann [436]1 year ago
7 0

See attachment for the area model of the equation 4x^2+12x+9 = (2x+3)^2

<h3>What are area models?</h3>

Area models are shapes used to model or illustrate products, multiplications, divisions and quotients

<h3>How to draw the area model?</h3>

The equation is given as:

4x^2+12x+9 = (2x+3)^2

Express (2x+3)^2 as the product of (2x+3) and (2x+3)

4x^2+12x+9 = (2x+3) * (2x+3)

The above means that the area model is a square.

So, the side lengths of the model must be equal, where the side lengths are 2x + 3 and the area of the square is 4x^2+12x+9

See attachment for the area model of the equation 4x^2+12x+9 = (2x+3)^2

Read more about area models at:

brainly.com/question/12245811

#SPJ1

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3 years ago
If f(x)=16x- 30 and g(x)= 14x-6, for which value of x does (f-g)(x)=0?
Georgia [21]

Answer:

x=12

Step-by-step explanation:

16x-30-(14x-6)=2x-24=0. add 24 on both sides to get 2x=24. divide by 2 on both sides to get x=12

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2 years ago
Find the probability of drawing 3 Aces at random from a deck of 52 ordinary playing cards if the cards are:_________
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Answer:

A) 1/2197

B) 1/5525

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome.

Since there are 52 random cards in a deck of card, the total outcome will be 52.

a) Also in a deck of card, there are 4 aces. If we are to select 3 aces with replacement, this means that each time we pick up an ace from the card, it was returned.

Pr(drawing an ace) = 4/52

Pr(drawing 3 aces and replacing it) = 4/52 *4/52*4/52

Pr(drawing 3 aces and replacing it) = 64/140,608

Pr(drawing 3 aces and replacing it) = 1/2197

b) If we pick 3 aces without replacement then each time we pick an ace, the total number cards keeps reducing.

Pr(picking the first ace) = 4/52

Pr(picking the second ace without replacing) = 3/51 (Since we didn't replace the first one, the total ace in the deck of card will reduce to 3 and the total will be 51)

Pr(picking the third ace without replacing) = 2/50 (since we didn't replace the first two aces, the total ace in the deck of card will reduce to 2 and the total will be 50)

Pr(drawing 3 aces without replacement) =  4/52*3/51*2/50

Pr(drawing 3 aces without replacement) =  24/132,600

Pr(drawing 3 aces without replacement) = 1/5525

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Step-by-step explanation:

16+10+4

26+4

30

30÷(2+2)

30÷4

7 1/2

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Two friends leave their houses at the same time and run across town towards each other. The first friend runs at a speed of 8 mi
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2 and a half hours estimate
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