The equation to be solved is: 3 [ 2 ^ (2t - 5) ] - 4 = 10
The steps are:
1) transpose - 4=> 3 [ 2^ (2t - 5) ] = 10 + 4
2) Combine like terms => 3 [2^ (2t - 5) ] = 14
3) Divide both terms by 3 => 2^ (2t - 5) = 14 / 3
4) Take logarithms of both sides => (2t - 5) log (2) = log (14/3)
5) Divide both sides by log (2) =>
log (14/3)
2t - 5 = -------------------
log (2)
6) transpose - 5+>
log (14/3)
2t = ------------------- + 5 = 2.22 + 5
log (2)
2t = 7.22
7) divide both sides by 2 => t = 7.22 / 2 = 3.61
To solve you move the variables to the side and divide both sides by the factor number that doesnt have the variables your answer would be b=23/2 as a decimal is 11.5
Answer and explanation:
Temperature:
If it was -5°C, you know that it is very cold and below freezing point (0°C), but if it was 20°C you know the weather is quite warm.
0°C is freezing point and is used as a reference point to be able to tell if the temperature is warm or not.
