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Sati [7]
2 years ago
10

Graph and label each of the ordered pairs in the coordinate plane. Then state the quadrant

Mathematics
1 answer:
Scrat [10]2 years ago
5 0

The quadrants of the points that needs to be graphed  are:

  • Quadrant 1- Points A and D
  • Quadrant 2- Points E and H
  • Quadrant 3- Points G and J
  • Quadrant 4- Points C
  • x-axis- Point F
  • y-axis- Point B and I

<h3>How do you get the quadrants?</h3>

Since the points that was given are:

A(2, 4)        B(0, -3)  

C(1, -1)       E(-4,1)    

G(-3,-2)      I(0, 2)

D(3, 3)        F(2,0)  

H(-2, 3)     J(-1,-4)

Then, we plot all the coordinate above on a graph (see image attached)

Hence, from the image attached graph, the categories that can be seen are:

Quadrant 1 is  Points A and D

Quadrant 2 is  Points E and H

Quadrant 3 is Points G and J

Quadrant 4 is Points C

x-axis-  Point F

y-axis- Point B and I

Learn more about quadrants from

brainly.com/question/28103714

#SPJ1

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Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
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The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

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We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

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Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

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4 years ago
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Drag each number to the correct location on the table.
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Answer:

\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}

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Step-by-step explanation:

Since we believe it  

The number sequence is that those which can be described as \frac{p}{q} and that is not ending and recurring.  Figures that are unreasonable are also the ones, that are not \frac{p}{q} and therefore are non-ending, non-recurring.  

The number sequence is 3\sqrt{25} = 3 \times 5 = 15

Rational amount since it is classified as \frac{p}{q}  .\frac{-11}{151} is really a rational number.  

1.\overline{1.625} is a real function, since it does not end but repeats it.  

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