Circumference of a circle = 2πr
So,
![circumference = 2\pi \: r \\ = > circumference = 2 \times \frac{22}{7} \times \frac{63 \: cm}{2} \\ = > circumference = 2 \times \frac{11}{7} \times 63 \: cm \\ = > circumference = 2 \times 11 \times 9 \: cm \\ = > circumference = 198 \: cm](https://tex.z-dn.net/?f=circumference%20%3D%202%5Cpi%20%5C%3A%20r%20%5C%5C%20%20%3D%20%20%3E%20circumference%20%3D%202%20%5Ctimes%20%20%5Cfrac%7B22%7D%7B7%7D%20%5Ctimes%20%20%5Cfrac%7B63%20%5C%3A%20cm%7D%7B2%7D%20%20%5C%5C%20%20%3D%20%20%3E%20circumference%20%3D%202%20%5Ctimes%20%20%5Cfrac%7B11%7D%7B7%7D%20%5Ctimes%2063%20%5C%3A%20cm%20%5C%5C%20%20%3D%20%20%3E%20circumference%20%3D%202%20%5Ctimes%2011%20%5Ctimes%209%20%5C%3A%20cm%20%5C%5C%20%20%3D%20%20%3E%20circumference%20%3D%20198%20%5C%3A%20cm)
Answer:
Using the level of significance to be 0.05.
Now the ratio of oil companies is given by 22/43=0.51
And the ratio of construction companies is 55/93=0.59
Hence we can conclude and accept the claim that proportion of oil companies that employ the method of risk transfer is less than the proportion of construction companies.
Step-by-step explanation:
First we find the ratio of both companies then we conclude from the result
Answer:
My answer to the question is option B
Answer:
Probability to get a fruit or flowering plant is ![\frac{13}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B30%7D)
Probability to get either a Neem or a peepa tree ![\frac{29}{60}](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B60%7D)
Step-by-step explanation:
The formula to find Probability is: ![\frac{No\,of\,\,favourable\,\,outcomes}{total\,\,outcomes}](https://tex.z-dn.net/?f=%5Cfrac%7BNo%5C%2Cof%5C%2C%5C%2Cfavourable%5C%2C%5C%2Coutcomes%7D%7Btotal%5C%2C%5C%2Coutcomes%7D)
First finding Total outcomes
Adding all the values given:
125+165+50+150+110 = 600
So, Total Outcomes = 600
- We need to find the Probability to get a fruit or flowering plant
Probability to get a fruit= 150
Probability to get a flowering plant= 110
No of favourable outcomes = 150+110 = 260
So, the probability will be:
![Probability=\frac{No\,of\,\,favourable\,\,outcomes}{total\,\,outcomes}](https://tex.z-dn.net/?f=Probability%3D%5Cfrac%7BNo%5C%2Cof%5C%2C%5C%2Cfavourable%5C%2C%5C%2Coutcomes%7D%7Btotal%5C%2C%5C%2Coutcomes%7D)
![Probability=\frac{260}{600} \\Probability=\frac{26}{60}\\Probability=\frac{13}{30}](https://tex.z-dn.net/?f=Probability%3D%5Cfrac%7B260%7D%7B600%7D%20%5C%5CProbability%3D%5Cfrac%7B26%7D%7B60%7D%5C%5CProbability%3D%5Cfrac%7B13%7D%7B30%7D)
So, Probability to get a fruit or flowering plant is ![\frac{13}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B30%7D)
- We need to find the Probability to get either a Neem or a peepa tree
Probability to get a Neem = 125
Probability to get a Peepal Tree= 165
No of favourable outcomes = 125+165 = 290
So, the probability will be:
![Probability=\frac{No\,of\,\,favourable\,\,outcomes}{total\,\,outcomes}](https://tex.z-dn.net/?f=Probability%3D%5Cfrac%7BNo%5C%2Cof%5C%2C%5C%2Cfavourable%5C%2C%5C%2Coutcomes%7D%7Btotal%5C%2C%5C%2Coutcomes%7D)
![Probability=\frac{290}{600} \\Probability=\frac{29}{60}](https://tex.z-dn.net/?f=Probability%3D%5Cfrac%7B290%7D%7B600%7D%20%5C%5CProbability%3D%5Cfrac%7B29%7D%7B60%7D)
So, Probability to get either a Neem or a peepa tree ![\frac{29}{60}](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B60%7D)