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S_A_V [24]
2 years ago
15

Using the table below, find the mean and median of the set of data.

Mathematics
1 answer:
Schach [20]2 years ago
5 0

The mean of the data set is 81.6.

The median of the data set is 80.

<h3>What is mean?</h3>

The mean is the average of a data set. Therefore,

Mean = (70 x 2 + 75 x 8 + 80 x 6 + 85 x 3 + 90 x 9) / 28 = 81.6.

Hence,

mean = 81.6

<h3>What is a median?</h3>

Median is a statistical measure that determines the middle value of a dataset listed in ascending order .

Therefore,

28 / 2 = 14

median = 80 + 80 / 2 = 160 / 2 = 80

learn more on mean and median here: brainly.com/question/28052298

#SPJ1

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Whats the quotient of 15.86 divided by 0.65?
spayn [35]

Answer:

24.4

Step-by-step explanation:

15.86 /0.65 = 24.4

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3 years ago
The sloping side of a cone is 10cm and the height is 8cm. find the radius of the base
amid [387]
You can use Pythagoras theorem to find the radius.

r^2 + 8^2 = 10^2

r^2 + 64 = 100

r^2 = 36

r = 6
3 0
3 years ago
Which pair of numbers is relatively prime A.)57 and 96 B.)68 and 118 C.)70 and 195 D.)143 and 323
creativ13 [48]
I think is D , hope i answer fast enough haha :D
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3 years ago
Read 2 more answers
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
scZoUnD [109]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<em>A) If the length of a rectangle was tripled, but the  width did not change?</em>

<em>Perimeter</em>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

<u>Area</u>

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em>

<u>Perimeter</u>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

<u><em>Area</em></u>

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

4 0
3 years ago
F(x) = 3(x + 2)2 – 6​
maksim [4K]
F(x)= 3 (x^2 + 4x +4) - 6
= 3x^2 + 12x +12 -6
= 3x^2 + 12x + 6
4 0
3 years ago
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