Step-by-step explanation:
I'll do 2.
Alright,Alex let say we have factored a quadratic into two binomial, for example

If we set both of those equal to zero

We can used the zero product property in this case to find the roots of the quadratic equation.
This means that

This means we set each binomal equal to zero to find it root.






So our roots are negative 3/5 and negative 2/3 using zero product property
Answer:
Step-by-step explanation:
ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.
Similar triangles so we can do
.
Solve for it we get 44y = 6x
Differentiate relative to time t, we get 44y' = 6x'.
change in x (x') is equal to 5. And we get the answer y' =
.
the
ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.
take a picture of the display counter too
X = approximately 633
Steps:
lnx + ln3x = 14
ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common
(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e
3x^2 = e^14 : e cancels out log on the left side and the right side is e^14
x^2 = e^14 / 3 : divide both sides by 3
√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2 on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself
x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>
x = </span>633.141449221 : solve
Answer:
Step-by-step explanation:
Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the
race at 10 kmph. If his total time for the entire race was 1.74 hours, how far did he run in
the first part of the race?
First part :
Total Distance = 12 km
First part Speed = 8kmph
Let distance covered on first part = x
Second part speed = 10kmhr
(8*x)