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2 years ago

You must write your answer in fully simplified form.2t= -12

Mathematics

1 answer:

Katarina [22]2 years ago

4 0

Answer:

t=-6

Step-by-step explanation:

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If r= 9 units and x = 4 units, then what is the volume of the cylinder shown above?

Thepotemich [5.8K]

Answer:

Volume of the cylinder is. 1017.36

Step-by-step explanation:

$V=\pi r^2h$ is the area of a cylinder.

Let's plug in our values.

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3.14 = pi

9 = radius

x = height

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V = (3.14)(9)^2(4)

V = (3.14)(81)(4)

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2 years ago

A bottom of a 6 foot deep circular pool has an area of 452.4 ft. If the pool is only

inna [77]

Answer:

450.4

Step-by-step explanation:

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3 years ago

20 points help w part b

Hatshy [7]

Answer:

8:07 am

Step-by-step explanation:

It takes 9 minutes to walk from his house to the bus station. It then takes 92 minutes for the bus to travel from Birmingham to Coventry. After arriving, he takes 12 minutes to reach his workplace. This takes a total of 113 minutes.

9 + 92 + 12 = 113

Convert 113 minutes to hours and minutes.

113 - 60 = 53

1 hr and 53 min

He has to be at work by 10. Subtract the time it takes to get to his work by the time he has to get there.

10 - 1 hr = 9

9 - 53 min = 8:07

The latest time he can leave is 8:07.

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3 years ago

What is 1.0836 rounded to the nearest thousandth

sp2606 [1]

1.084 because it goes tenths hundredths thousands

4 0

3 years ago

Read 2 more answers

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

You must write your answer in fully simplified form.2t= -12​

You must write your answer in fully simplified form.2t= -12